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2 years ago

What is the median of the data?

1 answer:

3 0

You need to order the data, so
11, 12, 13, 14, 14, 15, 17, 17, 18, 18, 18, 20
Then find the middle of the data. Because there are 12 data points, the median will lie between the two 6th placed numbers
The two numbers are 15 and 17, so work out the mean of them. (15+17)/2 = 16
So the answer is B. 16

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What’s the correct answer for this?

jek_recluse [69]

Answer:

I believe that the answer is 24.

6 0

2 years ago

Part A

Anuta_ua [19.1K]

Answer:

Part A: There are 4 zeros of the polynomial function f(x)

Part B: The zeroes of the polynomial function f(x) are -4, -1, 0, 2 ⇒ C

Step-by-step explanation:

The zeroes of a function are the x-coordinates of the point of intersection between the graph of the function and the x-axis (x-intercepts) which means values of x at y = 0

Part A:

In the given graph

∵ The graph of the function f(x) = - $x^{4}$ - 3x³ + 6x² + 8x intersects the x-axis

at 4 points

→ That means there are 4 values of x have y = 0

∴ The number of zeroes of the function is 4

∴ There are 4 zeros of the polynomial function f(x)

Part B:

∵ The graph intersects the x-axis at points (-4, 0), (-1, 0), (0, 0), (2, 0)

→ That means the values of x at y = 0 are -4, -1, 0, 2

∴ f(x) = 0 at x = -4, -1, 0, 2

∴ The zeroes of the polynomial function f(x) are -4, -1, 0, 2

4 0

2 years ago

Simplify -3p3 + 5p + (-2p 2) + (-4) - 12p + 5 - (-8p3). Select the answer in descending powers of p.

BigorU [14]

-3p^3 + 5p -2p^2 - 4 - 12p + 5 + 8p^3
5p^3 - 2p^2 - 7p + 1

It is the second choice

7 0

2 years ago

The board of a large company is made up of 7 women and 9 men. 6 of them will go as a delegation to a national conference.

Burka [1]

Answer:

a) 5765760

b) 60480

c) 5705280

Step-by-step explanation:

Assuming that order is not important:

Number of women = 7

Number of men = 9

Members of the delegation = 6

a) How many delegations are possible?

$n=\frac{16!}{(16-6)!}=16*15*14*13*12*11\\ n= 5765760$

b) How many of these delegations have all men?

$n_{men} = \frac{9!}{(9-6)!}=9*8*7*6*5*4 \\n_{men} = 60480$

c) How many of these delegations have at least one woman?

$n_{women >0}=n-n_{men}\\n_{women >0} =5765760-60480\\n_{women >0} =5705280$

4 0

2 years ago

Listed below are the overhead widths (in cm) of seals measured from photographs and the weights (in kg) of the seals. Construc

Anarel [89]

Answer and Step-by-step explanation: Scaterplot is a type of graphic which shows the relationship between to variables. In this question, you want to determine if there is a linear relationship between overhead widths of seals and the weights. So, the hypothesis are:

H₀: no linear correlation;

H₁: there is linear correlation;

In this hypothesis test, to reject H₀, the correlation coefficient r of the data set has to be bigger than the critical value from the table.

With α = 0.05 and n = 6, the critical value is 0.811.

The linear correlation is calculated as:

r = n∑xy - ∑x.∑y / √[n∑x² - (∑x)²] [n∑y² - (∑y)²]

r = $\frac{6.9632 - 51.1108}{\sqrt{6.439 - (51^{2} )}.6.14482 - (1108^{2} ) }$

r = 0.9485

Since r is bigger than the critical value, H₀ is rejected, which means there is enough evidence to conclude that there is linear correlation between overhead widths and the weights.

In the attachments is the scaterplot of the measurements, also showing the relationship.

5 0

2 years ago