3 years ago

Whats the equation in slope intercept form 2x-3y=-12

1 answer:

Natasha2012 [34]3 years ago

4 0

Each grade level 12 schools has 298 remember each part of the question is related to the other part and original problem if they are 13 grade level is how many students attend the school

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the product of 8 and a number x is equal to 32. write an algebraic expression, an equation, or an inequality

11111nata11111 [884]

8x = 32
x = 32/8
x = 4

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4 years ago

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1 Which point has coordinates (2, 2)?

Sindrei [870]

Answer:

Step-by-step explanation:

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If G( x ) = 3 x + 1, then G -1 (1) is...<br><br> -1/3<br> -4<br> -0

GarryVolchara [31]

Answer:

-4

Step-by-step explanation:

3+1 = 4 so just put a dash at the start and you ger -4

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3 years ago

What is 26 1/2 divided by 6 5/8??

mariarad [96]

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4 years ago

The curves y = √x and y=(2-x) and the Cartesian axes form two distinct regions in the first quadrant. Find the volumes of rotati

makkiz [27]

Answer:

Step-by-step explanation:

If you graph there would be two different regions. The first one would be

$y = \sqrt{x} \,\,\,\,, 0\leq x \leq 1 \\$

And the second one would be

$y = 2-x \,\,\,\,\,, 1 \leq x \leq 2$ .

If you rotate the first region around the "y" axis you get that

$A_1 = 2\pi \int\limits_{0}^{1} x\sqrt{x} dx = \frac{4\pi}{5} = 2.51$

And if you rotate the second region around the "y" axis you get that

$A_2 = 2\pi \int\limits_{1}^{2} x(2-x) dx = \frac{4\pi}{3} = 4.188$

And the sum would be 2.51+4.188 = 6.698

If you revolve just the outer curve you get

If you rotate the first region around the x axis you get that

$A_1 =\pi \int\limits_{0}^{1} ( \sqrt{x})^2 dx = \frac{\pi}{2} = 1.5708$

And if you rotate the second region around the x axis you get that

$A_2 = \pi \int\limits_{1}^{2} (2-x)^2 dx = \frac{\pi}{3} = 1.0472$

And the sum would be 1.5708+1.0472 = 2.618

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4 years ago