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Anettt [7]
3 years ago
6

A rectangular garden of area 75 ftö is bounded on three sides by a wall costing

Mathematics
1 answer:
ioda3 years ago
8 0
A = L * W = 75 so L = 75/W Cost = 4W + 8(2L + W) = 4W + 16L + 8W = 12W + 16L = 12W + 1200/W C' = (12(W^2 - 100))/(W^2) = (12(W-10)(W+10))/(W^2) so W = 10 then L = 7.5
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calculate the height at 3 seconds given that the rocket travels 85 feet per second and starts on a launch pad 15 feet of the gro
Airida [17]

Answer:

The height of the rocket at 3 seconds is 270 feet

Step-by-step explanation:

To calculate the height of the rocket at 3 seconds,

First, we will determine the height the rocket has traveled in 3 seconds

The height traveled by the rocket is given by

Height (h) = Velocity (v) × Time (t)

From the question,

The rocket travels 85 feet per second, that is the velocity of the rocket is 85 feet per second,

Now,

v = 85 feet / second

t = 3 seconds

Hence,

Height (h) = 85 feet /second × 3 seconds

Height = 255 feet

∴ the rocket would have traveled 255 feet in 3 seconds,

But, the rocket starts on a launch pad 15 feet of the ground,

Then, the height of the rocket at 3 seconds is

255 feet + 15 feet = 270 feet.

Hence, the height of the rocket at 3 seconds is 270 feet

4 0
3 years ago
Robert plans to make a box-and-whisker plot of the following set of data. 27, 14, 46, 38, 32, 18, 21 Which of the following shou
Simora [160]
To make a box and whisker plot, you need to draw a number line that would be able to represent all the values in the data (look at your lowest and highest numbers).

You will need to graph the following 5 points on your number line (median, lower quartile, lower extreme, upper quartile, and upper extreme).

Create a box around the quartiles and extend the lines to the extremes.
See the picture I have attached for the box and whisker box for this data set.

7 0
3 years ago
Help please!!!!! (QUESTION #3)!!!!!!!
Paha777 [63]
I’m not sure I’m just guessing but maybe 7x minus 35
7 0
3 years ago
In the given diagram if AB || CD, ∠ABO = 118° , ∠BOD = 152° , then find the value of ∠ODC.
GaryK [48]

Answer:

90°

Step-by-step explanation:

Through point O draw a ray on left side of O which is || to AB & CD and take any point P on it.

Therefore,

∠ABO + ∠BOP = 180° (by interior angle Postulate)

118° + ∠BOP = 180°

∠BOP = 180° - 118°

∠BOP = 62°.... (1)

Since, ∠BOP + ∠POD = ∠BOD

Therefore, 62° + ∠POD = 152°

∠POD = 152° - 62°

∠POD = 90°.....(2)

∠POD + ∠ODC = 180° (by interior angle Postulate)

90° + ∠ODC = 180°

∠ODC = 180° - 90°

\huge\red {\boxed {m\angle ODC =  90°}}

6 0
3 years ago
I need help with this question. "Complete the function table for the given domain, and plot the points on the graph f(x)=-x^2+2x
Anna71 [15]

Answer:

Step-by-step explanation:

i just did this problem wrong and it showed me the correct answer

4 0
3 years ago
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