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Tom [10]
3 years ago
15

Which correctly describes a cross section of the square pyramid? Select three options. A square pyramid with 2 foot sides. A cro

ss section parallel to the base is a square with side lengths of 2 ft. A cross section parallel to the base is a square with side lengths of less than 2 ft. A cross section perpendicular to the base through the top vertex is a triangle with the same dimensions as the triangular sides of the pyramid. A cross section perpendicular to the base through the top vertex is a triangle with different dimensions than the triangular sides of the pyramid. A cross section that is perpendicular to the base that does not pass through the top vertex of the pyramid is a trapezoid.
Mathematics
2 answers:
77julia77 [94]3 years ago
8 0

its C and D i think good luck people

<3

kicyunya [14]3 years ago
3 0

Answer:

Step-by-step explanation:

A cross section perpendicular to the base through the top vertex is a triangle with the same dimensions as the triangular sides of the pyramid.

A cross section perpendicular to the base through the top vertex is a triangle with different dimensions than the triangular sides of the pyramid.

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If one tosses a coin three times, write dow nthe possible observed number of heads and their probabilities
seropon [69]
You need to find the probability of Heads, Heads, Heads in 3 tosses;

P(HHH)= (1/2)(1/2)(1/2) <-- each toss has 2 possibilities and heads is one 
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Therefore, the probability of flipping 3 heads on a fair coin is 1/8 

Hope I helped :) 
6 0
3 years ago
Can I have help help on 22,24,26,28,30 please
Dmitriy789 [7]
I'll do 22 for you. 22, 24, 26, 28, and 30, are very similar to each other.

PROPORTIONS:
Draw it out.

5/7 = either c/6, or b/5. 
I'll do c/6
5/7 = c/6
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4 0
3 years ago
Multiply <br> 0.105 x 0.7=
Keith_Richards [23]

Answer:

0.0735

Step-by-step explanation:

0.105×0.7=0.0735

8 0
3 years ago
Read 2 more answers
Find the<br>common factors of 5x²y and - 3x​
rusak2 [61]
The common factor of 5x2 is y5x
4 0
3 years ago
The A&amp;M Hobby Shop carries a line of radio-controlled model racing cars. Demand for the cars is assumed to be constant at a
Bond [772]

Answer:

Step-by-step explanation:

A) Demand per month= 40 cars

Annual Demand (D)= 12*40 = 480

Fixed Cost per order (K)= 15

Holding Cost= 20% of cost= 60 *0.2 = 12

a. Economic Order Quantity=

Q^{*}={\sqrt {{\frac {2DK}{h}}}}

= √(2*480*15)/12

=34.64 ~ 35

Total Cost =P*D+K(D/EOQ)+h(EOQ/2) P= Cost per unit

= 60*480+ 15(480/35) + 12(35/2)

= 28800+ 205.71+ 210

=$29215.71

B). Backorder Cost (b)= $45

Qbo= Q* × √( b+h/ h)

= 35*√(12+45/ 45)

= 35* 1.12

=39.28 ~ 39

Shortage (S)= Qbo * (K/K+b)

= 39* (15/15+45)

= 39* 0.25

= 9.75

Total Cost Minimum=( bS2/ 2Qbo) + P (Qbo- S)2/2Qbo + K(D/Qbo)

=45* 9.752 / 2* 392 + 60 (39-9.75)2/ 2* 392 + 15 ( 480/39)

= 1.40+ 21.9.+ 184.61

=$207.91

C)Length of backorder days (d) = Demand ÷ amount of working days

d = 480 ÷ 300

d = 1.6

Calculate the backorders as the maximum number of backorders divided by the demand per day

s/d = 9.75/1.6 = 6.09 days (answer)

D) Calculate the difference in total between not using backorder:

$207.85 + $207.85 - 207.91 = $207.79

The saving in using backorder is $207.79.

Therefore I would recommend using a backorder

6 0
3 years ago
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