A line passes through (2, −1) and (4, 5).

Mathematics

1 answer:

mote1985 [20]2 years ago

8 0

Shouldn't it be y=3x-7?

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Factor 15x3 – 5x2 + 6x – 2 by grouping

Tanzania [10]

5x2(3x-1)+2(3x-1)factoring furhter gives(5x2+2)(3x-1)

8 0

3 years ago

Which of the following is a area of the special trepezoid if ab=19,cd=19 and the height is 14

tankabanditka [31]

As, Opposite side of Special trapezoid is equal.So, it will be a Parallelogram.

ab=c d= 19 units

Height of Trapezoid = 14 units

Area of Trapezoid = $\frac{1}{2} \times {\text{Sum of parallel sides}} \times {\text{Perpendicular Distance between them}}$

$=\frac{1}{2}\times (19+19) \times 14\\\\ =\frac{1}{2} \times 38 \times 14\\\\ = 19 \times 14\\\\= 266$

So, Area of Trapezoid = 266 square units

You, can use the formula for finding the area of parallelogram,which is = Base on which perpendicular is drawn × Length of Altitude

= 19 × 14

= 266 square units

5 0

3 years ago

You synthetic division to find P(3) for p(x)=x^4-6x^3-4x^2-6x-2

klio [65]

By the polynomial remainder theorem, the remainder upon dividing $p(x)$ by $x-3$ will be the value of $p(3)$ .

... | 1 ... -6 ... -4 ... -6 .... -2
3. | .. ... 3 ... -9 ... -39 .. -135
--------------------------------------
... | 1 ... -3 ... -13 . -45 .. -137

So you have

$\dfrac{x^4-6x^3-4x^2-6x-2}{x-3}=x^3-3x^2-13x-45-\dfrac{137}{x-3}$

which means $p(3)=-137$ .