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Alex Ar [27]
3 years ago
10

i require some assistance :(, please help ASAP. Click an item in the list or group of pictures at the bottom of the problem and,

holding the button down, drag it into the correct position in the answer box. Release your mouse button when the item is place. If you change your mind, drag the item to the trashcan. Click the trashcan to clear all your answers. Use the definitions and theorems of this section to evaluate and simplify the following expression. Be sure to express answers with positive exponents. (b^2)^3
Mathematics
1 answer:
Irina-Kira [14]3 years ago
5 0

Answer:

My guess is 2b^5

Step-by-step explanation:

This question is kinda tricky. LMK if its correct

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a central angle of circle of radius 50cm intercept an arc of 10 cm .Express central angle in radian n in degree​
Elodia [21]

Answer:

11.7 degrees approximated to 12 degrees

Step-by-step explanation:

couldn't send the answer as 1 photo

7 0
3 years ago
Which equation describes this line?
kvasek [131]

Answer:

I think it's c but I'm not 100 percent sure

7 0
3 years ago
Read 2 more answers
Let R be the relation on the set of ordered pairs of positive integers such that ((a, b), (c, d)) ∈ R if and only if ad = bc. Ar
Veseljchak [2.6K]

Answer:

The given relation R is equivalence relation.

Step-by-step explanation:

Given that:

((a, b), (c, d))\in R

Where R is the relation on the set of ordered pairs of positive integers.

To prove, a relation R to be equivalence relation we need to prove that the relation is reflexive, symmetric and transitive.

1. First of all, let us check reflexive property:

Reflexive property means:

\forall a \in A \Rightarrow (a,a) \in R

Here we need to prove:

\forall (a, b) \in A \Rightarrow ((a,b), (a,b)) \in R

As per the given relation:

((a,b), (a,b) ) \Rightarrow ab =ab which is true.

\therefore R is reflexive.

2. Now, let us check symmetric property:

Symmetric property means:

\forall \{a,b\} \in A\ if\ (a,b) \in R \Rightarrow (b,a) \in R

Here we need to prove:

\forall {(a, b),(c,d)} \in A \ if\ ((a,b),(c,d)) \in R \Rightarrow ((c,d),(a,b)) \in R

As per the given relation:

((a,b),(c,d)) \in R means ad = bc

((c,d),(a,b)) \in R means cb = da\ or\ ad =bc

Hence true.

\therefore R is symmetric.

3. R to be transitive, we need to prove:

if ((a,b),(c,d)),((c,d),(e,f)) \in R \Rightarrow ((a,b),(e,f)) \in R

((a,b),(c,d)) \in R means ad = cb.... (1)

((c,d), (e,f)) \in R means fc = ed ...... (2)

To prove:

To be ((a,b), (e,f)) \in R we need to prove: fa = be

Multiply (1) with (2):

adcf = bcde\\\Rightarrow fa = be

So, R is transitive as well.

Hence proved that R is an equivalence relation.

8 0
3 years ago
Is (2,2) a solution to x+y=4 and 5x+5y=20?
telo118 [61]

Answer:

yes

Step-by-step explanation:

(2,2)

x=2 y=2

x+y=4

2+2=4

4=4

5x+5y=20

5(2)+5(2)=20

10+10=20

20=20

7 0
3 years ago
Give an example how to use a number line to multiply a 2 digit number by 20
mariarad [96]
You would start on x(x being the 2 digit number)and to multiply it by 20 you would move to the right x amount of spaces repeating this process 20 times.
3 0
3 years ago
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