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Alex Ar [27]
3 years ago
10

i require some assistance :(, please help ASAP. Click an item in the list or group of pictures at the bottom of the problem and,

holding the button down, drag it into the correct position in the answer box. Release your mouse button when the item is place. If you change your mind, drag the item to the trashcan. Click the trashcan to clear all your answers. Use the definitions and theorems of this section to evaluate and simplify the following expression. Be sure to express answers with positive exponents. (b^2)^3
Mathematics
1 answer:
Irina-Kira [14]3 years ago
5 0

Answer:

My guess is 2b^5

Step-by-step explanation:

This question is kinda tricky. LMK if its correct

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<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B3%7D%7B2n%7D%20%2B%20%5Cfrac%7B1%7D%7Bn%5E2%7D%20%3D%20%20%5Cfrac%7Bn-2%7D%7B2n%5
Sergio [31]
Make denomenators the same
common denom is 2n²

multiply 3/2n by n/n
mulitply 1/n² by 2/2

we get
\frac{3n}{2n^2}+\frac{2}{2n^2}=\frac{n-2}{2n^2}
combine fractions
\frac{3n+2}{2n^2}=\frac{n-2}{2n^2}
multiply both sides by 2n²
2n+2=n-2
minus n both sides
n+2=-2
minus 2 both sides
n=-4
8 0
3 years ago
14+6 :)) ILL GIVE BRAINLIEST ITS 100 POINTS :))
emmainna [20.7K]

Answer:

20

Step-by-step explanation:

lol

3 0
3 years ago
8. What is the 10th term of the geometric sequence
kkurt [141]

Answer:

n=10

a10= - 3 (2)^(10-1)= -3(2)^9

= -1536

6 0
3 years ago
Y varies directly as x if x=15 when y=20, find x when y=30
mixas84 [53]

Answer:

X=22.5

Step-by-step explanation:

Y=kX

20=15k

k=4/3

For X when Y=30

30=4/3×X

Cross multiply

4X=90

X=22.5

6 0
3 years ago
A single die is rolled one time. Find the probability of rolling a number greater than 4 or less than 3.
Vika [28.1K]

<u>Answer: </u>

The probability of rolling a number greater than 4 or less than 3 is \frac{2}{3}

<u>Solution: </u>

In the given question there are two events as follows:

(a) Rolling a number greater than 4 i.e. A = {5,6}

(b) Rolling a number less than 3 i.e. B = {1,2}

Since a die has 6 numbers,

 P(A) = \frac{2}{6} where P(A) is the probability of occurrence of event A and P(B) = \frac{2}{6}

Since, Event A and Event B has nothing in common therefore they are mutually exclusive events.

P(A∪B) = P(A) + P(B)

=\frac{2}{6}+\frac{2}{6}

=\frac{4}{6}

=\frac{2}{3}

Therefore the probability of getting a number greater than 4 or less than 3 is \frac{2}{3}

7 0
3 years ago
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