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satela [25.4K]
4 years ago
10

There are 100 seniors and 80 juniors in the homecoming parade. The students split up into groups of even size, to fit on the par

ade floats. They want the most students possible on each float, with just juniors or just seniors on each float. How many students should be on each float?
Mathematics
1 answer:
Lorico [155]4 years ago
6 0

Answer:

20

Step-by-step explanation:

Number of juniors = 80

Number of seniors = 100

To obtain the same and highest number of student on each float ; we find the highest common factor :

____80 ___100

_2__40___50

_2__20___25

_5__ 4____5

The highest common factor = (2 * 2 * 5) = 20

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3 years ago
Please help me its a propotional question and answer of Z Y X
tino4ka555 [31]
Since the only two corresponding side you have are 10 units and 4 units, you can divide these two numbers to get the scale factor.

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5 0
3 years ago
I'm doing integers one step equations what is s-1=10
sergeinik [125]
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3 0
3 years ago
Read 2 more answers
Part 1. Please show work. Please assist me with these math problems. ​
Vitek1552 [10]

Answer: 1) 2, 3, 4, 9, 32, 279, 8896, 2481705, 22077238784

              2) 2,490,924

              3) Neither

<u>Step-by-step explanation:</u>

S_n=S_{n-2}\cdot (S_{n-1}-1)\quad \\\\S_1=2\quad given\\S_2=3\quad given\\S_3=S_1(S_2-1)\quad =2(3-1)\quad =4\\S_4=S_2(S_3-1)\quad =3(4-1)\quad =9\\S_5=S_3(S_4-1)\quad =4(9-1)\quad =32\\S_6=S_4(S_5-1)\quad =9(32-1)\quad =279\\S_7=S_5(S_6-1)\quad =32(279-1)\quad =8,896\\S_8=S_6(S_7-1)\quad =279(8896-1)\quad =2,481,705\\S_9=S_7(S_8-1)\quad =8896(2481705-1)\quad =22,077,238,784

\sum^8_{k=1}S_k\\\\=S_1+S_2+S_3+S_4+S_5+S_6+S_7+S_8\\\\= 2,490,924\\

Neither

Not arithmetic because the difference between each of the terms is not the same.            

                        S₂ - S₁          S₃ - S₂           S₄ - S₃      

                      3 - 2 = 1       4 - 3 = 1          9 - 4 = 5

Not geometric because the ratios between each of the terms is not the same.                

                       \dfrac{S_2}{S_1}=\dfrac{S_3}{S_2}\qquad \rightarrow \dfrac{3}{2}=\dfrac{4}{3}\qquad \rightarrow \text{cross multiply to get}: 9\neq 8

8 0
3 years ago
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