Feet i think, thats how they lable the size of a home when your buying
im not 100% sure though
Point slope form is y-y1= m(x-x1) where m is slope and y1 and x1 are the x and y of the coordinate given.
y-1= 2(x-(-2))
y-1= 2(x+2)
Final answer: y-1= 2(x+2)
If you do in fact mean 
(as opposed to one of these being the derivative of 
at some point), then integrating twice gives
From the initial conditions, we find
Eliminating 
, we get
![C_1 = -\dfrac{\ln(6)}5 = -\ln\left(\sqrt[5]{6}\right) \implies C_2 = \ln\left(\sqrt[5]{6}\right)](https://tex.z-dn.net/?f=C_1%20%3D%20-%5Cdfrac%7B%5Cln%286%29%7D5%20%3D%20-%5Cln%5Cleft%28%5Csqrt%5B5%5D%7B6%7D%5Cright%29%20%5Cimplies%20C_2%20%3D%20%5Cln%5Cleft%28%5Csqrt%5B5%5D%7B6%7D%5Cright%29)
Then
![\boxed{f(x) = \ln|x| - \ln\left(\sqrt[5]{6}\right)\,x + \ln\left(\sqrt[5]{6}\right)}](https://tex.z-dn.net/?f=%5Cboxed%7Bf%28x%29%20%3D%20%5Cln%7Cx%7C%20-%20%5Cln%5Cleft%28%5Csqrt%5B5%5D%7B6%7D%5Cright%29%5C%2Cx%20%2B%20%5Cln%5Cleft%28%5Csqrt%5B5%5D%7B6%7D%5Cright%29%7D)
9514 1404 393
Answer:
9
Step-by-step explanation:
For studs 16" O.C., Chalberg will need 9: one at the beginning of each of the 16" spaces in the 96" width of the wall, and one at the end. That's a total of 6+1 = 7 studs.
The top and bottom edges of the wall are each 8', so will require 1 more board each.
The total number of boards Chalberg needs is 9.
But there is no problem here
