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azamat
3 years ago
14

Write the equation of the line with the slope =5 and that goes through point (3,-5)

Mathematics
1 answer:
viva [34]3 years ago
6 0

Answer:

y=5x-20

Step-by-step explanation:

Point-slope form.

\frac{y-(-5)}{x-3} = 5\\y+5 = 5x-15\\y=5x-20

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Given f(x) = 3 and g(x) = 5x + 7, find (f + g)(-8).
levacccp [35]

Answer:

-30

Step-by-step explanation:

f(x) = 3 so f(-8) = 3;

g(x) = 5x + 7, so g(-8) = 5(-8) + 7 = -33

Then (f + g)(-8) = 3 - 33 = -30

This is the sum of two functions both evaluated at x = -8.

4 0
3 years ago
Which is the height of the triangle?<br> ( PIC IS PROVIDE PLS HELP ME)
zysi [14]
<h3>Answer: 80 meters</h3>

This is an isosceles triangle. The dashed line is the height which is perpendicular to the base 120. The height is always perpendicular to the base. The dashed line cuts the base into two equal pieces (this only works for isosceles triangles when you cut at the vertex like this).

So we have two smaller triangles each with a base of 60 and a height of x. Focus on one of the right triangles and use the pythagorean theorem to solve for x.

a^2 + b^2 = c^2

x^2 + (60)^2 = (100)^2

x^2 + 3600 = 10000

x^2 = 10000 - 3600

x^2 = 6400

x = sqrt(6400)

x = 80

Each smaller right triangle has side lengths of 60, 80, 100

Note the ratio 60:80:100 reduces to 3:4:5. A 3-4-5 right triangle is a very common pythagorean primitive.

5 0
3 years ago
Read 2 more answers
Whats is 1+1+3+7+8+33542
Murljashka [212]

Answer:

33562, You could have used a calculator, or used your head, why

Step-by-step explanation:

7 0
3 years ago
What is the quotient (2x^2 + 12x +18 ) divided by (x +3)
katen-ka-za [31]
2(x^2+6x+9) = 2(x+3)^2

So after divided by (x+3), answer will be:

2(x+3)
6 0
3 years ago
What is the value of a over 6 plus 3 if a=48
AlexFokin [52]
Hello there!

By a over 6, I assume you mean a / 6? And by the wording, I assume 3 is outside of the fraction.

For the three outside the fraction,

(a / 6) + 3
(48 / 6) + 3
8 + 3
= 11

Hoped this help! If you have any more questions or need any more assistance, don't hesitate to friend me and message me! I can provide a mini lesson and a in-depth explanation as to what I did and why.
5 0
3 years ago
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