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SpyIntel [72]
4 years ago
14

Drag each statement to show whether it is true, based on the graph.

Mathematics
2 answers:
brilliants [131]4 years ago
6 0

Answer:

The price per one pound of almonds equal $2.20/0.65 lb

0.65 pounds of almonds cost $2.20

Step-by-step explanation:

Verify each case

case 1) The price per one pound of almonds equal $2.20/0.65 lb

<em>The statement is true</em>

To find the price per one pound calculate the unit rate

so

$2.20/0.65 lb=$3.38 per one pound

case 2) 2.2 pounds of almonds cost $0.65

The statement is not True

The correct is 0.65 pounds of almonds cost $2.2

case 3) Each bag of almonds weighs 2.2 pounds

Cannot be determined

In the problem there is no information about how much each bag of almonds weighs

case 4) 0.65 pounds of almonds cost $2.20

The statement is True

The point (0.65,2.20) lie to the line of the the graph

Airida [17]4 years ago
4 0

Answer:

1.True

2.Not true

3.Cannot be determined

4.True

Step-by-step explanation:

From given graph we can see that

Weight takes along x- axis and cost takes along y-axis .

The given point is (0.65,2.2)

It means

Weight =0.65 lbs

Cost=$2.2

By unitary method

Cost of 0.65 pounds of almonds=$2.2

Cost of 1 pound of almonds=\frac{2.2}{0.65} =$3.38

1.The price per pound of almonds equals to \frac{2.2}{0.65}

This is true.

2.2.2 pounds of almonds cost $0.65.

It is not true because cost of 0.65 pounds of almonds equals to $2.2.

3.Each bag of almonds weighs 2.2 pounds.

From given graph , weight of each bag cannot be determined.

4.0.65 pounds of almonds costs $2.2.

It is true statement because cost of 0.65 pounds of almonds equals to $2.2

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fgiga [73]
Least to greatest

1.04, 1.0494, 1.2, 1.33
5 0
3 years ago
Solve: 10 2/3+2h≤4 1/3
PtichkaEL [24]

Answer:

\large\boxed{h\leq-\dfrac{19}{6}\to h\in\left(-\infty,\ -\dfrac{19}{6}\right]}

Step-by-step explanation:

\text{First convert the mixed numbers to the improper fractions:}\\\\10\dfrac{2}{3}=\dfrac{10\cdot3+2}{3}=\dfrac{32}{3}\\\\4\dfrac{1}{3}=\dfrac{4\cdot3+1}{3}=\dfrac{13}{3}\\\\\text{Solve the inequality}\\\\10\dfrac{2}{3}+2h\leq4\dfrac{1}{3}\\\\\dfrac{32}{3}+2h\leq\dfrac{13}{3}\qquad\text{multiply both sides by 3}\\\\3\!\!\!\!\diagup^1\cdot\dfrac{32}{3\!\!\!\!\diagup_1}+3\cdot2h\leq3\!\!\!\!\diagup^1\cdot\dfrac{13}{3\!\!\!\!\diagup_1}\\\\32+6h\leq13\qquad\text{subtract 32 from both sides}\\\\6h\leq-19\qquad\text{divide both sides by 6}\\\\h\leq-\dfrac{19}{6}

6 0
3 years ago
Can I get help plz ?!? Mark BRAINLIEST?
maw [93]

Answer:

2

Step-by-step explanation:

Perimeter of a rectangle = 2(length + breadth)

=> 2{2x + (x + 4)) = 20

=> (2x + x + 4) = 20/2 = 10

=> 3x + 4 = 10

=> 3x = 10 - 4 = 6

=> x = 6/3 = 2

Here, according to the diagram

Length = 2x = 2(2) = 4

Breadth = x + 4 = 2+4 = 6

But breadth should always be lesser than the length. From this, it can be concluded that the actual breadth is 2x and actual length is x + 4, for perimeter to be 20.

7 0
3 years ago
Read 2 more answers
Plz be a kind person and help me solve this...
sukhopar [10]

Answer:

630

Step-by-step explanation:

10 times 21= 210÷2= 105

35×21=735-105=630

4 0
4 years ago
If a quadrilateral has 2 pairs of opposite sides that are congruent, then it is a parallelogram.​
STatiana [176]

Answer:

it is actually a quadrilateral  

Step-by-step explanation:

3 0
3 years ago
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