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SpyIntel [72]
3 years ago
14

Drag each statement to show whether it is true, based on the graph.

Mathematics
2 answers:
brilliants [131]3 years ago
6 0

Answer:

The price per one pound of almonds equal $2.20/0.65 lb

0.65 pounds of almonds cost $2.20

Step-by-step explanation:

Verify each case

case 1) The price per one pound of almonds equal $2.20/0.65 lb

<em>The statement is true</em>

To find the price per one pound calculate the unit rate

so

$2.20/0.65 lb=$3.38 per one pound

case 2) 2.2 pounds of almonds cost $0.65

The statement is not True

The correct is 0.65 pounds of almonds cost $2.2

case 3) Each bag of almonds weighs 2.2 pounds

Cannot be determined

In the problem there is no information about how much each bag of almonds weighs

case 4) 0.65 pounds of almonds cost $2.20

The statement is True

The point (0.65,2.20) lie to the line of the the graph

Airida [17]3 years ago
4 0

Answer:

1.True

2.Not true

3.Cannot be determined

4.True

Step-by-step explanation:

From given graph we can see that

Weight takes along x- axis and cost takes along y-axis .

The given point is (0.65,2.2)

It means

Weight =0.65 lbs

Cost=$2.2

By unitary method

Cost of 0.65 pounds of almonds=$2.2

Cost of 1 pound of almonds=\frac{2.2}{0.65} =$3.38

1.The price per pound of almonds equals to \frac{2.2}{0.65}

This is true.

2.2.2 pounds of almonds cost $0.65.

It is not true because cost of 0.65 pounds of almonds equals to $2.2.

3.Each bag of almonds weighs 2.2 pounds.

From given graph , weight of each bag cannot be determined.

4.0.65 pounds of almonds costs $2.2.

It is true statement because cost of 0.65 pounds of almonds equals to $2.2

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Determine the measure of each segment then indicate whether the statements are true or false
kupik [55]

Answer:

d_{AB}\ne d_{JK}

d_{AB}\ne \:d_{GH}

d_{GH}\ne \:d_{JK}

Therefore,

Option (A) is false

Option (B) is false

Option (C) is false

Step-by-step explanation:

Considering the graph

Given the vertices of the segment AB

  • A(-4, 4)
  • B(2, 5)

Finding the length of AB using the formula

d_{AB}\:=\:\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}

        =\sqrt{\left(2-\left(-4\right)\right)^2+\left(5-4\right)^2}

         =\sqrt{\left(2+4\right)^2+\left(5-4\right)^2}

         =\sqrt{6^2+1}

         =\sqrt{36+1}

        =\sqrt{37}

d_{AB}\:=\sqrt{37}

d_{AB}=6.08 units        

Given the vertices of the segment JK

  • J(2, 2)
  • K(7, 2)

From the graph, it is clear that the length of JK = 5 units

so

d_{JK}=5 units

Given the vertices of the segment GH

  • G(-5, -2)
  • H(-2, -2)

Finding the length of GH using the formula

d_{GH}\:=\:\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}

         =\sqrt{\left(-2-\left(-5\right)\right)^2+\left(-2-\left(-2\right)\right)^2}

          =\sqrt{\left(5-2\right)^2+\left(2-2\right)^2}

          =\sqrt{3^2+0}

           =\sqrt{3^2}

\mathrm{Apply\:radical\:rule\:}\sqrt[n]{a^n}=a,\:\quad \mathrm{\:assuming\:}a\ge 0

d_{GH}\:=\:3 units

Thus, from the calculations, it is clear that:

d_{AB}=6.08  

d_{JK}=5

d_{GH}\:=\:3

Thus,

d_{AB}\ne d_{JK}

d_{AB}\ne \:d_{GH}

d_{GH}\ne \:d_{JK}

Therefore,

Option (A) is false

Option (B) is false

Option (C) is false

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2 years ago
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