Answer:
Average velocity of the function over the given interval
= 
Step-by-step explanation:
<u><em>Explanation:-</em></u>
Given function y = 3/x -2 ...(i)
The average velocity of the function over the given interval
Average velocity = 
= 
now integrating
= 
= 
= 
by using formulas
log a-log b = log(a/b)
on simplification , we get
= 
= 
Average velocity of the function over the given interval
= 
w = mg
w/m = g
69N / 12kg = 5.75 N/kg
<u>Answer: B) 5.75 m/s2</u>