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2 years ago

Solve the eequation show all your work g + 5 = 7 1/5

Mathematics

2 answers:

topjm [15]2 years ago

7 0

Answer:

Move all terms not containing

to the right side of the equation.

Exact Form:

46/5

Decimal Form:

9.2

Mixed Number Form:

9 1/5

Masja [62]2 years ago

4 0

Answer:

g = 2 1/5

Step-by-step explanation

get g by itself by canceling out the 5

whatever you do to one side you have to do to the other side.

5-5 leaves you with nothing but the g on the left side of the equals sign

7 1/5 -5= 2 1/5

so your left with g= 2 1/5

g + 5 = 7 1/5

-5 -5

g = 2 1/5

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The University of Washington claims that it graduates 85% of its basketball players. An NCAA investigation about the graduation

Nonamiya [84]

Probabilities are used to determine the chances of events

The given parameters are:

Sample size: n = 20
Proportion: p = 85%

<h3>(a) What is the probability that 11 out of the 20 would graduate? </h3>

Using the binomial probability formula, we have:

$P(X = x) = ^nC_x p^x(1 - p)^{n -x}$

So, the equation becomes

$P(x = 11) = ^{20}C_{11} \times (85\%)^{11} \times (1 - 85\%)^{20 -11}$

This gives

$P(x = 11) = 167960 \times (0.85)^{11} \times 0.15^{9}$

$P(x = 11) = 0.0011$

Express as percentage

$P(x = 11) = 0.11\%$

Hence, the probability that 11 out of the 20 would graduate is 0.11%

<h3>(b) To what extent do you think the university’s claim is true?</h3>

The probability 0.11% is less than 50%.

Hence, the extent that the university’s claim is true is very low

<h3>(c) What is the probability that all 20 would graduate? </h3>

Using the binomial probability formula, we have:

$P(X = x) = ^nC_x p^x(1 - p)^{n -x}$

So, the equation becomes

$P(x = 20) = ^{20}C_{20} \times (85\%)^{20} \times (1 - 85\%)^{20 -20}$

This gives

$P(x = 20) = 1 \times (0.85)^{20} \times (0.15\%)^0$

$P(x = 20) = 0.0388$

Express as percentage

$P(x = 20) = 3.88\%$

Hence, the probability that all 20 would graduate is 3.88%

<h3>(d) The mean and the standard deviation</h3>

The mean is calculated as:

$\mu = np$

So, we have:

$\mu = 20 \times 85\%$

$\mu = 17$

The standard deviation is calculated as:

$\sigma = np(1 - p)$

So, we have:

$\sigma = 20 \times 85\% \times (1 - 85\%)$

$\sigma = 20 \times 0.85 \times 0.15$

$\sigma = 2.55$

Hence, the mean and the standard deviation are 17 and 2.55, respectively.

Read more about probabilities at:

brainly.com/question/15246027

8 0

2 years ago

The tax on a property with an assessed value of $90,000 is $1,200. What is the assessed value of a property if the tax is $2,200

Ivanshal [37]

I'm not 100% sure but this is how I would try.
If you don't get a better answer, check this w/your teacher.

x/100 *90,000 = 1200

90,000x = 120,000

x = 1.3% tax percentage

1.3/100x = 2200

1.3x = 220,000

x = $169,230.77 assessed value

5 0

3 years ago

A manufacturer of paper coffee cups would like to estimate the proportion of cups that are defective (tears, broken seems, etc.)

Maksim231197 [3]

Answer:

The 95% confidence interval is $0.0503 < p < 0.1297$

The sample proportion is $\r p = 0.09$

The critical value is $Z_{\frac{\alpha }{2} } = 1.96$

The standard error is $SE =0.020$

Step-by-step explanation:

From the question we are told that

The sample size is n = 200

The number of defective is k = 18

The null hypothesis is $H_o : p = 0.08$

The alternative hypothesis is $H_a : p > 0.08$

Generally the sample proportion is mathematically evaluated as

$\r p = \frac{18}{200}$

$\r p = 0.09$

Given that the confidence level is 95% then the level of significance is mathematically evaluated as

$\alpha = 100 - 95$

$\alpha = 5\%$

$\alpha = 0.05$

Next we obtain the critical value of $\frac{ \alpha }{2}$ from the normal distribution table, the value is

$Z_{\frac{\alpha }{2} } = 1.96$

Generally the standard of error is mathematically represented as

$SE = \sqrt{\frac{\r p (1 - \r p)}{n} }$

substituting values

$SE = \sqrt{\frac{0.09 (1 - 0.09)}{200} }$

$SE =0.020$

The margin of error is

$E = Z_{\frac{ \alpha }{2} } * SE$

=> $E = 1.96 * 0.020$

=> $E = 0.0397$

The 95% confidence interval is mathematically represented as

$\r p - E < \mu < p < \r p + E$

=> $0.09 - 0.0397 < \mu < p < 0.09 + 0.0397$

=> $0.0503 < p < 0.1297$

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3 years ago

For the data in the table, write an equation for the direct variation.

melisa1 [442]

The equation of direct variation is,

$\begin{gathered} y=kx \\ k=\frac{y}{x} \end{gathered}$

Substitute the values of <em>y</em> and <em>x</em>.

$\begin{gathered} k=\frac{5.4}{4} \\ k=1.35 \end{gathered}$

So, the obtained equation will be <em>y</em>=1.35(x).

Let's check with the values of <em>x</em>.

1) If <em>x</em>=4

$\begin{gathered} y=1.35x \\ y=1.35(4) \\ y=5.4 \end{gathered}$

2) If <em>x</em>=2

$\begin{gathered} y=1.35x \\ y=1.35(2) \\ y=2.7 \end{gathered}$

3) If <em>x</em>=-2

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11 months ago

The length of the hypotenuse of a right triangle is 157 units. The length of one leg of the triangle is 132. Lara wrote the foll

ASHA 777 [7]

the correct answer for this is the last choice:

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3 years ago

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