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3 years ago

Find m (2x+14) (X+7)

Mathematics

1 answer:

LekaFEV [45]3 years ago

4 0

Answer:

Step-by-step explanation:

Ⓗⓘ ⓣⓗⓔⓡⓔ

Well, assuming m of angle ABD is 90 degrees, then you would add and then solve.

2x+14+x+7=90

3x+21=90

3x=69

(っ◔◡◔)っ ♥ Hope this helped! Have a great day! :) ♥

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10 points

oee [108]

Answer:

x = 240 feet

Step-by-step explanation:

It is given that,

The angle of depression is 30 degrees from the bottom of the boat to a deep sea diver at the depth of 120 ft.

We need to find the distance x the diver must swim up to the boat. It can be calculate by applying trigonometry as follows :

$\sin30=\dfrac{120}{x}\\\\x=\dfrac{120}{\sin30}\\\\x=240\ \text{feet}$

So, the distance the diver must swim up to the boat is 240 feet.

6 0

3 years ago

| 9. The distance between Town A and Town B was 108 km. A car and a van left Town A at 12 00 for Town B. On reaching Town B, the

Westkost [7]

Answer:

a) Time until both vehicles meet is 1.5 hours after starting at noon. That makes it 1:30PM.

b) Average speed of car is 84 km/h

Step-by-step explanation:

A -----------------------z------------B

Left Speed(km/h) Time

Car: 12PM X

Van: 12PM 60

Car/Van

DistanceCar AB + z

DistanceVan Az

Ratio: (AB+z)/Az = 7/5

Time until both meet = T (in hours)

Distance Car: xT

Distance Van: 60T

====

xT = AB + z

60T = Az

---

(xT/60T)= (7/5)

x = 60(7/5)

x = 84 km/h

=====

Time for car to reach B is: time (hr) = 108 km/(84 km/h)

time = 1.286 hours

Distance for at 1.289 hours is: distance (km) = (60 km/h)*(1.286 h)

distance = 77.14 km

At 1.286 hours, the car reverses direction. The van is (108 km - 77.14 km) or 30.86 km away.

Add the distances travelled by both vehicles after the car reverses direction at 1.286 hours. The sum will be 30.86 km when they meet, at time of T.

Car Distance + Van Distance = 30.86 km

T(84 km/h) + t(60 km)

They meet when they are 0 km apart, which can be modeled with the following equation:

Van travel Distance - Car Travel Distance = 0 starting at 1.286 hr.

Let t be the time after 1.286 hours that both vehicles meet/collide.

t*(60 km/h) + t(84 km/h) = 30.86 km

t(60+84) = 30.86 km

t(144 km/h) = 30.86 km

t = 0.2143 hr

Total time until the car and van meet is 1.286 hr + 0.2143 hr for a total of 1.50 hours.

=================

a) Time until both vehicles meet is 1.5 hours after starting at noon. That makes it 1:30PM.

b) Average speed of car is 84 km/h

==============

CHECK

Is the ratio of the distance travelled by the car and the van until they meet in the ratio of 7/5?

Car distance is (1.5 hr)(84 km/h) = 126 km

Van distance is (1.5 hr)(60 km/h) = 90.0 km

Ratio is 126/90 or 1.4

Ratio of 7/5 is 1.4

YES

3 0

2 years ago

The height of a sunflower increases from 82cm to 1 metre in a week.find the percentage increase in height

KATRIN_1 [288]

Find difference i.e 100-82=18
if 82 is 100%, what about 18?
(18*100)/82= 21.951 ans

5 0

3 years ago

HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP

babunello [35]

A+b = 5
b+c= 3 1/2
2 times 2 + 3 = 7
a times d =8
c+c = 1
(e)2 = 1/9

8 0

3 years ago

Read 2 more answers

Find the answer The weight of an elephant is 10 to the 3rd power times the weight of a cat .If the the elephant weighs 14,000 po

Hitman42 [59]

Answer:

$14\ pounds$

Below is the procedure that was used to find the answer.

Step-by-step explanation:

Let be "e" the weight in pounds of the elephant and "c" the weight in pounds of the cat.

According to the information provided in the exercise, we know that The weight of an elephant is $10^3$ times the weight of a cat. Based on this we can write the following equation:

$e=10^3c$

If the weight in pounds of the elephant is:

$e=14,000$

We must substitute this value into the equation and then solve for "c" in order to find the weight in pounds of the cat.

Then we get:

$14,000=10^3c\\\\\frac{14,000}{10^3}=c\\\\c=14$

3 0

3 years ago