Answer:
Jay started with $148.5 and Kay with $24.75.
Step-by-step explanation:
With the information provided you know that Jay had 6 times as much money as Kay wich can be expressed as:
J=6K, where
J is the money Jay had
K is the money Kay had
Also, you know that Jay gave Kay $33 and Jay now has twice as much money as Kay, which would be:
J-33=2(K+33)
Now, you can replace J=6K in this equation and solve for K:
6K-33=2K+66
6K-2K=66+33
4K=66
K=24.75
Then, you can replace the value of K in J=6K:
J=6*24.75
J=148.5
According to this, the answer is that Jay started with $148.5 and Kay with $24.75.
Answer:
Part 1) Australia 
Part 2) China 
Part 3) Mexico 
Part 4) Zaire 
Step-by-step explanation:
we know that
The equation of a exponential growth function is given by

where
P(t) is the population
t is the number of years since year 2000
a is he initial value
r is the rate of change
Part 1) Australia
we have

substitute


Find the expected population in 2025,
Find the value of t
t=2005-2000=5 years
substitute the value of t in the equation

Part 2) China
we have

substitute


Find the expected population in 2025,
Find the value of t
t=2005-2000=5 years
substitute the value of t in the equation

Part 3) Mexico
we have

substitute


Find the expected population in 2025,
Find the value of t
t=2005-2000=5 years
substitute the value of t in the equation

Part 4) Zaire
we have

substitute


Find the expected population in 2025,
Find the value of t
t=2005-2000=5 years
substitute the value of t in the equation

3. straight line
8.obtuse
12.acute
I would 100 because the more the trials means the more the results which means you get more of an accurate experiment then if you only did 10. Because since you have so many answers from all of the experiments you can conclude the correct answer from all of the experiments. I hope you get what I’m trying to say