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Gre4nikov [31]
3 years ago
12

Investment of 1000 at 16% interest rate for 20 years

Mathematics
1 answer:
andreev551 [17]3 years ago
7 0
This might be wrong but, 320.

I used the formula for simple interest which is I=Prt, thus giving me this:

I = 1000 (.016) (20)

Hope this helps at all!
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The graph below shows the distance, y, in miles, of a bird from its nest for a certain amount of time, x, in minutes:
Montano1993 [528]

Answer:

0.2 miles per minute represents the speed of the bird and 3 miles represents the original distance of the bird from its nest.

Step-by-step explanation:

As there is no graph mentioned here but the information are quite sufficient to answer the question.

We have points (0,3), (5,4),(10,5)...

From these points we can find the slope of the line .

From point slope formula y-y_1=m(x-x_1)

And assigning (x,y) (0,3) and (x_1,y_1) (5,4)

m=\frac{y_1-y}{x_1-x} =\frac{4-3}{5-0} =\frac{1}{5}=0.2

This slope is also the speed of the bird which is 0.2\ miles\ per\ minute.

As by plugging the values of any coordinate point we can confirm this.

Lets put (10,5), y-axis is the distance so in 10 minutes the the distance covered by the bird must be equal to to y-axis value which is 5 miles.

y=0.2(x),y=0.2(10)=5\ miles

Now as in t=0 the bird has started from y-intercept value 3 so we can say that,the original distance of the bird from its nest is 3\ miles.

So the correct choices are:B and D

The birds speed is 0.2\ miles per minute and is 3\ miles away from its nest.

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3 years ago
Compare Elena's and Noah's money using fraction
Leokris [45]
Um did you get the wrong picture?
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Use the power series for 1 1−x to find a power series representation of f(x) = ln(1−x). What is the radius of convergence? (Note
Viktor [21]

a. Recall that

\displaystyle\int\frac{\mathrm dx}{1-x}=-\ln|1-x|+C

For |x|, we have

\displaystyle\frac1{1-x}=\sum_{n=0}^\infty x^n

By integrating both sides, we get

\displaystyle-\ln(1-x)=C+\sum_{n=0}^\infty\frac{x^{n+1}}{n+1}

If x=0, then

\displaystyle-\ln1=C+\sum_{n=0}^\infty\frac{0^{n+1}}{n+1}\implies 0=C+0\implies C=0

so that

\displaystyle\ln(1-x)=-\sum_{n=0}^\infty\frac{x^{n+1}}{n+1}

We can shift the index to simplify the sum slightly.

\displaystyle\ln(1-x)=-\sum_{n=1}^\infty\frac{x^n}n

b. The power series for x\ln(1-x) can be obtained simply by multiplying both sides of the series above by x.

\displaystyle x\ln(1-x)=-\sum_{n=1}^\infty\frac{x^{n+1}}n

c. We have

\ln2=-\dfrac\ln12=-\ln\left(1-\dfrac12\right)

\displaystyle\implies\ln2=\sum_{n=1}^\infty\frac1{n2^n}

4 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Csqrt%7B%5C%5C%5Cfrac%7B9%2B%5Csqrt%7B17%7D%20%7D%7B2%7D" id="TexFormula1" title="\sqrt{\\\f
Alborosie

\huge\underline\pink{✏ANSWER}

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Fantom [35]

Answer:

139558.6

Step-by-step explanation:

8 0
2 years ago
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