NEED HELP ASAP!!!! PLEASEEE

Mathematics

1 answer:

nikdorinn [45]2 years ago

5 0

The first answer of the missing blank is 4/5.

The second answer of the missing blank is 2.

The third answer of the missing blank is 25.

*For all of these solutions, I will be using the common rules for logarithms.*

Solution for the first question:

Log9^4/5 must equal log9^4-log9^5, or it could also equal the more proper version, which is simplified: 2log9^2-log9^5.

Solution for the second question:

Log3^22 must equal log3^11+log3^2, if you break it down.

Solution for the third question:

Log9^25 must equal 2log9^5 because it will be like this when simplifying it:

log9^25=2log9^5

log9^5²=2log9^5

2log9^5=2log9^5

These are all of the step-by-step procedures for all three of these given questions. Anyways, I hope that this helped you!

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I need help in solving this problem (ASAP)

zhannawk [14.2K]

Answer:

The answer is y=24

Step-by-step explanation:

The triangle is a 30-60-90 triangle, which means that the it follows the respective ratio of x:x $\sqrt{3}$ :2x. Since we know that the 30 degree value is 8 $\sqrt{3}$ , we can establish that the 60 degree value is 8 $\sqrt{3}$ * $\sqrt{3}$ = 24.

4 0

2 years ago

Quadrilateral ABCD is inscribed in this circle.

Anna [14]

A quadrilateral, has 4 sides and its internal angles sum, add up to 360, now... you have 3 angles give.. .but we don't have C

so.. C is the difference of all the three angles from 360 or $\bf \measuredangle C=360-x-(2x+1)-148\implies \measuredangle C=360-x-2x-1-148$ whatever that is, now, you'll get some value in x-terms

so.... now once we know what C is

you can if you want, do a search in google for "inscribed quadrilateral conjecture", I can do a quick proof if you need one

but in short, for a quadrilateral inscribed in a circle, each pair of opposites angles are "supplementary angles", namely they add up to 180°

so.. what the dickens does all that mean? well D+B=180 and A+C = 180

now. we know what A is, 2x+1
and by now, you'd know what C is from 360-x-2x-1-148

so... add them together then and

$\bf \begin{array}{cccclllll}
A&+&C&=&180\\
\uparrow &&\uparrow \\
(2x+1)&+&(360-x-2x-1-148)&=&180
\end{array}$

solve for "x"

6 0

2 years ago

Read 2 more answers

Please help giving brainlest!! no links no unnecessary comments thank you :)

seraphim [82]

Answer:

Last point is at (7,-3)

Step-by-step explanation: