Answer:
Y'=3xy-3x-12
Y'=F(-2,-1)=0
Step-by-step explanation:
The function of the equation at the point (-2,-1)
is where the equation make the function go to zero:
Y'=3xy-3x-12
Y'=F(-2,-1)=[3(-2)(-1)]-[3(-1)]-12
F(-2,-1)=[6]-[-6]-12
F(-2,-1)=6+6-12
F(-2,-1)=12-12
F(-2,-1)=0
Solving for y
3xy-3x-12=0
y=4/x+x
Making y=0
So the values make the function go to zero
Answer:
35
Step-by-step explanation:
49*5/7
=35
Answer: x=−9/4
Step-by-step explanation:
Let's solve your equation step-by-step.
−2(x+14)+1=5
Step 1: Simplify both sides of the equation.
−2(x+14)+1=5(−2)(x)+(−2)(14)+1=5(Distribute)−2x+
−1
2
+1=5
(−2x)+(
−1
2
+1)=5(Combine Like Terms)
−2x+
1
2
=5
−2x+
1
2
=5
Step 2: Subtract 1/2 from both sides.
−2x+
1
2
−
1
2
=5−
1
2
−2x=
9
2
Step 3: Divide both sides by -2.
−2x
−2
=
9
2
−2
x=
−9
4
Answer: a) , where 'A' is the value of car after 't' years.
b) $12446.784
Step-by-step explanation:
Given: A new car that sells for $21,000 depreciates (decreases in value) 16% each year.
Then a function that models the value of the car will be
, where 'P' is the selling price of car, 'r' is the rate of depreciation in decimal, 't' is the time in years and 'A' is the value of car after 't' years.
Thus after substituting given value, the function becomes
To find the value after 3 years, substitute t=3 in the above function.
Hence the value of car after 3 years=$12446.784
