Answer:
a)
#include <iostream>
using namespace std;
int main() {
bool a,b,c;
cin>>a>>b;
if(a^b)//X-OR operator in C++.
c=true;
else
c=false;
cout<<c;
return 0;
}
b)
#include <iostream>
using namespace std;
int main() {
bool a,b,c,d;
cin>>a>>b>>c;
if((a^b)^c)//X-OR operator in C++.
d=true;
else
d=false;
cout<<d;
return 0;
}
Explanation:
The above written programs are in C++.There is an operator (^) called X-OR operator in C++.It returns true if the number of 1's are odd and returns false if the number of 1's are even.
In the if statement I have user X-OR operator(^) to find the result and storing the result in another boolean variable in both the questions.
I think C is correct I looked into some Python and that would seam like the most logical answer
The answer it is A i hope is good
Answer:
Explanation:
The following code is written in Python. It asks the user to enter the current balance and the annual interest rate. It then calculates the monthly interest rate and uses that to detect the interest that will be earned for the next month. Finally, printing that to the screen. A test output can be seen in the attached picture below.
balance = int(input("Enter current Balance: "))
interest = int(input("Enter current annual interest %: "))
interest = (interest / 12) / 100
next_month_interest = balance * interest
print('$ ' + str(next_month_interest))
Answer:
Option B and C are the correct answer for the above question
Explanation:
The above question asked about the work of the programmer to catch an error of the program--
- Then the option B states that the programmer needs to prints the value of the various program variable on every line of the program which is the correct solution because it is used to find the error easily. It defines the value of every variable in every place of the program and the programmer caught the error statement in the program if anywhere the variable gets the false value.
- The C option states to help from a friend, it is also a good solution because the friend can easily be caught the error of the program by seeing every line of code.
- But the other option is not correct because the option A states that the change the name of the variable which is not a result of anything.
- And the option D states that the code will be retyped again which is also not justify anything.