Answer: 4 days (I think)
Step-by-step explanation:
One cat = 150*2 = 300g
Two cats = 600g
600*2 = 1200 (this is the total amount of food they both eat in a day)
5kg = 5000g
1200g/5000g = 4.17
The bag will last 4 days.
Answer:
the cost of running the boarding
house for 600 students is N61,000
Step-by-step explanation:
Let C represents cost
K1 represents first constant
K2 represents second constant
C= k1+k2n
3500 = k1 + 25 k2............. Eqn(1)
6000= k1 + 50 k2 .............. Eqn(2)
Subtract eqn(1) from eqn(2)
2500= 25k2
K2= 2500/25
K2= 100
To get k1 from eqn(1)
3500 = k1 + 25 k2
Substitute the value of k2
3500 = k1 + 25 (100)
3500= k1 +2500
K1= 3500- 2500
K1= 1000
The equation connecting them;
C= 1000+ 100n
The cost of running the boarding
house for 600 students is
n= 600
C= 1000+ 100(600)
C= 1000+60000
C= N 61,0000
M=2-(-6)/(-1)-(-2)=8
Y=8x+b
-6=8*(-2)+b
-6=-16+b
B=16-6=10
Y=8x+10
I hope my answer is help to you
Answer:
The reflection is and classic reflection across the y-axis as the y stay the same and the x does not.
