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Harman [31]
3 years ago
14

"a man drove 10 mi directly east from his home, made a left turn at an intersection, and then traveled 5 mi north to his place o

f work. if a road was made directly from his home to his place of work, what would its distance be to the nearest tenth of a mile?"

Mathematics
2 answers:
Mariulka [41]3 years ago
6 0

Answer:

11.2 miles


Step-by-step explanation:

We can create a triangle from the information given.

<u>We can call the starting point (0,0) in the coordinate system.</u>

  • <u>10 mi east</u> - 10 miles to the right. then,
  • <u>5 mi north</u> - 5 miles above

<em><u>See the attached picture. The direct distance is labeled as x.</u></em>


Now we need to find x using pythagorean theorem.

Pythagorean Theorem = leg²+leg²=hypotenuse²

Solving for x:

10^2+5^2=x^2\\100+25=x^2\\125=x^2\\x=\sqrt{125}\\x=11.18


<em>Rounding to nearest tenth, we have </em><em>11.2 miles</em>

mario62 [17]3 years ago
5 0

This problem can be directly solved using the hypotenuse formula. Taking 10 mi and 5 mi as the two sides of the triangle, we find for the hypotenuse (distance directly from his home to his place of work):

c^2 = 10^2 + 5^2

c^2 = 100 + 25

c = 11.18 m

<span>c = 11.2 meters</span>

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Refer to the attached image.

Given: m \angle A = 65^\circ and measure of exterior angle at C = 117^\circ.

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