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2 years ago

Identify the scale factor when we scale up from Figure S to T. Just write the number.

Mathematics

1 answer:

Sergeu [11.5K]2 years ago

3 0

Answer:

Scale factor = 4

Step-by-step explanation:

Scale factor = $\frac{\text{Dimension of the image}}{\text{Dimension of preimage or original}}$

Since, S is being dilated with a scale factor to form T,

So, the figure S is the preimage and figure T will be the image,

Length of one side of image T = 8

Length of one side of preimage = 2

Therefore, Scale factor = $\frac{8}{2}$

= 4

Scale factor by which figure S has been dilated to form figure T is 4.

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Solve the following equation<br>1) 2c + c + 12 = 78

Annette [7]

Step-by-step explanation:

(2c+c) + 12 =78

3c + 12 = 78

78 - 12 = 66

66 ÷ 3 = 22

22 + 22 + 22 + 12 = 78

{ C = 22 }

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3 years ago

Round 30713.517126 to the nearest hundred.

larisa86 [58]

Answer:

3,266.53

Step-by-step explanation:

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3 years ago

Please help.........

Alex

Answer:

- $\frac{61}{11}$

Step-by-step explanation:

$\frac{x}{y}$ = $\frac{5}{6}$ ( cross- multiply )

6x = 5y ( divide both sides by 6 )

x = $\frac{5}{6}$ y

Then

$\frac{5x+6y}{5x-6y}$ ← substitute x = $\frac{5}{6}$ y into the expression

= $\frac{\frac{25}{6}y+6y }{\frac{25}{6}y-6y }$

= $\frac{\frac{61}{6}y }{-\frac{11}{6}y }$

= $\frac{\frac{61}{6} }{-\frac{11}{6} }$

= $\frac{61}{6}$ × - $\frac{6}{11}$

= - $\frac{61}{11}$

3 0

3 years ago

What is the value,in degree, of y

Viktor [21]

Y= 122.

I did the math.

6 0

2 years ago

Read 2 more answers

Roma sherry drove 80 miles from her home town to her parents' town. during her return trip, she was able to increase her speed

mr_godi [17]

<span>Answer: Roma Sherry drove 330 miles from her hometown to Tucson. During her return trip, she was able to increase her speed by 11 mph. If her return trip took 1 hour less time, find her original speed and her speed returning home. : Let s = original speed then (s+11) = return speed : Write a time equation: Time = distance%2Fspeed : Original time = return time + 1 hr 330%2Fs = 330%2F%28%28s%2B11%29%29 + 1 : Multiply equation by s(s+11) and you have: 330(s+11) = 330s + s(s+11) : 330s + 3630 = 330s + s^2 + 11s : 0 = 330s - 330s + s^2 + 11s - 3630 : A quadratic equation: s^2 + 11s - 3630 = 0 Factor this to: (s + 66)(s - 55) = 0 Positive solution s = 55 mph is original speed. : Find the time 330/55 = 6 hr, original time and 330/66 = 5 hrs, faster time; confirms our solution.</span>

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3 years ago