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worty [1.4K]
3 years ago
8

Given that a randomly chosen quadrilateral has four right

Mathematics
2 answers:
xeze [42]3 years ago
8 0

Answer:

it think this question is 25%

STALIN [3.7K]3 years ago
5 0

Answer: 25%

Step-by-step explanation:

Bc I’m smort boi

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PLS ANSWER I WILL MARK AS BRAINLIEST PLS
3241004551 [841]

Answer:

yes bc if u do it regular 3 divided by 2/3 is 4.5

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
A tablet PC contains 3217 music files. The distribution of file size is highly skewed with many small files. Suppose the true me
m_a_m_a [10]

Answer:

Let X the random variable who represents the file sizeof music. We know the following info:

\mu =2.3,\sigma =3.25

We select a sample of n=50 nails. That represent the sample size.  

Since the sample size is large enough n >30, we can use the central limit theorem. From this theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And we can approximate the distribution of the sample mean as a normal distribution and no matter if the distribution for X is right skewed or no.

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Let X the random variable who represents the file sizeof music. We know the following info:

\mu =2.3,\sigma =3.25

We select a sample of n=50 nails. That represent the sample size.  

Since the sample size is large enough n >30, we can use the central limit theorem. From this theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And we can approximate the distribution of the sample mean as a normal distribution and no matter if the distribution for X is right skewed or no.

8 0
3 years ago
The pointer of the vibration measuring instrument is observed to move between the 0.1 and0.3 marks on the vertical scale, when s
Norma-Jean [14]

Answer:

Step-by-step explanation:

Given points moves b/w 0.1 of 0.3 marks Hence amplitude is 0.2

Also , frequency (w) = 100 rad/s.

Natural frequency (wn) = √K/m

K = 20 N/mm x 1000mm/1m = 20000N/M

W = 1000mm/1m = 20,000N/M

FormulaX = FolK/1 - (w/wn)²

0.2 = b/20000/1 - (100/50)²

Given forcing frequency was doubled, W1 = 2 x 100=200rad/s

X1 =b/20,000/1 - (200/20)²

0.2/11 = 1 - (200/50)²/1 - (100/50)² = 0.2/11 = -15^5– 3

X1 = 0.04

8 0
3 years ago
I need help please help me !!!!
Zinaida [17]
It is a function because the input does not repeat itself.
8 0
3 years ago
What is the perimeter of this figure
lesantik [10]

Answer:

11+11+3+3+3= 31

Step-by-step explanatio

7 0
3 years ago
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