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expeople1 [14]
3 years ago
10

How can I find an outlier in a box and whisker plot?

Mathematics
1 answer:
Temka [501]3 years ago
4 0

Answer:

Generally it's one that is just out of the way, the extreme outcast.

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Find the axis of symmetry of the graph of the function. (5 points) f(x) = 3x2 + 12x + 9
Kryger [21]

Considering the definition of axis of symmetry, the axis of symmetry of the graph of the function f(x) = 3x²+ 12x+ 9 is x=-2.

<h3>Axis of symmetry</h3>

An axis of symmetry is an imaginary reference line that, when dividing any shape into two parts, its opposite points are equidistant from each other, that is, they are symmetrical.

In other words, the axis of symmetry is a vertical line that divides the parabola into two congruent halves.

The axis of symmetry is the line perpendicular to the "x" axis that contains the vertex of the function, that is, it always passes through the vertex of the parabola. So the x-coordinate of the vertex is the equation of the axis of symmetry.

That is, in a quadratic function that has the form:

f(x)= ax² + bx + c

the axis of symmetry is a vertical line and it is defined as x=\frac{-b}{2a}.

<h3>Axis of symmetry of f(x) = 3x² + 12x + 9</h3>

In this case, you know:

  • a= 3
  • b=12
  • c=9

Replacing in the definition of axis of symmetry:

x=\frac{-12}{2x3}

Solving:

x=\frac{-12}{6}

<u><em>x= -2</em></u>

Finally, the axis of symmetry of the graph of the function f(x) = 3x²+ 12x+ 9 is x=-2.

Learn more about axis of symmetry:

brainly.com/question/24737967

brainly.com/question/10473291

#SPJ1

3 0
2 years ago
In triangle MNO shown below, segment NP is an altitude:
Effectus [21]

Answer:  C. Definition of an Altitude

Step-by-step explanation:

Given: In triangle MNO shown below, segment NP is an altitude from the right angle.

Let ∠MNP=x

Then ∠PNO=90°-x

Therefore in triangle MNO,

∠MPN=∠NPO =90°  [by definition of Altitude]

[Definition of altitude : A line which passes through a vertex of a triangle, and joins the opposite side forming right angles. ]

Now using angle sum property in ΔMNP

∠MNP+∠MPN+∠PMN=180°

⇒x+90°+∠PMN=180°

⇒∠PMN=180°-90°-x

⇒∠PMN=90°-x

Now, in ΔMNO and ΔPNO

∠PMN=∠PNO=90°-x

and ∠MPN=∠NPO =90°  [by definition of altitude]

Therefore by AA similarity postulate, we have

ΔMNO ≈ ΔPNO

5 0
3 years ago
When will there be 0 pennies in the jar?how did you figured this out?
siniylev [52]
23 3/4 rounds because you can take 95 divided by 4 to get 23 3/4 rounds
6 0
3 years ago
I really need help please
GalinKa [24]

Answer:

  B, C, E, F

Step-by-step explanation:

The following relationships apply.

  • the diagonals of a parallelogram bisect each other
  • the diagonals of a rectangle are congruent
  • the diagonals of a rhombus meet at right angles
  • a rectangle is a parallelogram
  • a parallelogram with congruent adjacent sides is a rhombus

__

CEDF has diagonals that bisect each other, and it has congruent adjacent sides. It is a parallelogram and a rhombus, but not a rectangle. (B and C are true.)

ABCD has congruent diagonals that bisect each other. It is a parallelogram and a rectangle, but not a rhombus. (There is no indication adjacent sides are congruent, or that the diagonals meet at right angles.) (E and F are true.)

The true statements are B, C, E, F.

4 0
2 years ago
If the circumference of a circle is 12, and the angle measure of an arc is 60o, which is the length of the arc?
Kaylis [27]
We can get the measurement of the arc by determining first the radius of the circle. The circumference of a circle is equal to 2 * pi * radius. Hence from a 12 unit2 circumferenced circle, the radius is 1.91 units.Length of the arc is equal to radius times the angle in radians. 60 deg is equal to pi over 3. The length of the arc is equal to 2 units.
3 0
3 years ago
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