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saveliy_v [14]
3 years ago
14

Evaluate the expression. 4! • 3! 12 U 30 144 5 040

Mathematics
1 answer:
lukranit [14]3 years ago
8 0
4!•3! = 144
you’re welcome :)
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SS
Tanzania [10]

Answer:

c = 160 - 3(45)

Step-by-step explanation:

if c = the number of characters left;

160 = maximum number of characters that can be used in a text

3*45 = number of characters in sentences already used. (There are 3 sentences of 45 characters.)

(# of char left) = (max # char) - (# char already used) so:

c = 160 - 3*(45)

c = 160 - 135

c = 25

8 0
3 years ago
What’s the answer to this problem?
Sergio039 [100]

Answer: the answer is 0

Step-by-step explanation:

4 0
3 years ago
A circle has a diameter of 8m. What is its circumference?
Maslowich
The answer should be 25.12
6 0
3 years ago
PLEASE NO SPAM!!!! I REALLY NEED TO GET A GOOD GRADE ON THIS!
kenny6666 [7]

Answer:

I think it is A

Step-by-step explanation:

3 0
2 years ago
Inequality to x2 < 64
Anarel [89]
              NOT MY WORDS TAKEN FROM A SOURCE!

(x^2) <64  => (x^2) -64 < 64-64 => (x^2) - 64 < 0 64= 8^2    so    (x^2) - (8^2) < 0  To solve the inequality we first find the roots (values of x that make (x^2) - (8^2) = 0 ) Note that if we can express (x^2) - (y^2) as (x-y)* (x+y)  You can work backwards and verify this is true. so let's set (x^2) - (8^2)  equal to zero to find the roots: (x^2) - (8^2) = 0   => (x-8)*(x+8) = 0       if x-8 = 0 => x=8      and if x+8 = 0 => x=-8 So x= +/-8 are the roots of x^2) - (8^2)Now you need to pick any x values less than -8 (the smaller root) , one x value between -8 and +8 (the two roots), and one x value greater than 8 (the greater root) and see if the sign is positive or negative. 1) Let's pick -10 (which is smaller than -8). If x=-10, then (x^2) - (8^2) = 100-64 = 36>0  so it is positive
2) Let's pick 0 (which is greater than -8, larger than 8). If x=0, then (x^2) - (8^2) = 0-64 = -64 <0  so it is negative3) Let's pick +10 (which is greater than 10). If x=-10, then (x^2) - (8^2) = 100-64 = 36>0  so it is positive Since we are interested in (x^2) - 64 < 0, then x should be between -8 and positive 8. So  -8<x<8 Note: If you choose any number outside this range for x, and square it it will be greater than 64 and so it is not valid.

Hope this helped!

:)
7 0
2 years ago
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