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3 years ago

7

Which graph represents a function??

2 answers:

Angelina_Jolie [31]3 years ago

8 0

Answer:

To be a function a graph must pass the vertical line test and the only one that does this is the bottom right one.

e-lub [12.9K]3 years ago

6 0

Answer:

Bottom Right

Step-by-step explanation:

A function has only one y value for every x value. The upper left graph has many y values for the x value of 1, the bottom left graph has two y values for each x value and so does the upper right graph. the Bottom right graph is the only option with one y value for every x value.

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Fill in the blank to make the fractions equivalent 2/3 = Blank/15

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In ABC, what is the value of x?<br><br> Pls hurry im on a time limit here

kiruha [24]

Answer:

70

Step-by-step explanation:

By exterior angle theorem:

$(2x + 12) \degree = 112 \degree + 180 \degree - 2x \degree \\ \\ (2x + 12) \degree = 292 \degree - 2x \degree \\ \\ (2x + 12) \degree + 2x \degree = 292 \degree \\ \\ (2x + 12 + 2x) \degree = 292 \degree \\ \\ (4x + 12) \degree = 292 \degree \\ \\ 4x + 12 = 292 \\ \\ 4x = 292 - 12 \\ \\ 4x = 280 \\ \\ x = \frac{280}{4} \\ \\ x = 70$

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3 years ago

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3 years ago

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s2008m [1.1K]

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Step-by-step explanation:

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3 years ago

Read 2 more answers

2 tan 30°<br>II<br>1 + tan- 300

shusha [124]

Question:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$

Answer:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= sin(60^{\circ})$

Step-by-step explanation:

Given

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$

Required

Simplify

In trigonometry:

$tan(30^{\circ}) = \frac{1}{\sqrt{3}}$

So, the expression becomes:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2 * \frac{1}{\sqrt{3}}}{1 + (\frac{1}{\sqrt{3}})^2}$

Simplify the denominator

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2 * \frac{1}{\sqrt{3}}}{1 + \frac{1}{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\frac{2}{\sqrt{3}}}{1 + \frac{1}{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\frac{2}{\sqrt{3}}}{ \frac{3+1}{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\frac{2}{\sqrt{3}}}{ \frac{4}{3}}$

Express the fraction as:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2}{\sqrt 3} / \frac{4}{3}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2}{\sqrt 3} * \frac{3}{4}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{1}{\sqrt 3} * \frac{3}{2}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{3}{2\sqrt 3}$

Rationalize

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{3}{2\sqrt 3} * \frac{\sqrt{3}}{\sqrt{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{3\sqrt{3}}{2* 3}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\sqrt{3}}{2}$

In trigonometry:

$sin(60^{\circ}) = \frac{\sqrt{3}}{2}$

Hence:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= sin(60^{\circ})$

3 0

3 years ago