If y=(x+3)2 then (-2x-6)2 must equal what

Peggy was taking a timed 60-question test. She was able to correctly answer 70% of the questions but had to skip the rest. How m

Goryan [66]

The answer should be 42.

Since there are 60 questions in the test and she managed to answer 70% of the questions correctly, that means that she answered 70% out of 60 questions correctly.

So you need to calculate how much 70% out of 60 is. Since % is always measured on a base from 0 (%) to 100(%), then 70% is equal to the fraction 70/100, simplified to 7/10. To know how much 7/10 out of 60 is,you just multiplie them and your answer will be 42.

I hope this helps you forward.

4 0

3 years ago

I have a two digit number the sum of the digits is 12 the first digit is 4 Less Than 3 times the second what is my number

nignag [31]

Answer:

84

Step-by-step explanation:

Let the first digit = x

Let the second digit =y

x + y = 12

x + 4 = 3*y

===========

From the second equation, we learn that x = 3y - 4

Put that into the first equation.

3y - 4 + y = 12 Combine the left side

4y - 4 = 12 Add 4 to both sides

4y = 16 Divide by 4

4y/4 = 16/4

y = 4

=================

x + 4 = 12

x + 4 - 4 = 12-4

x = 8

So the number is 84

3 0

3 years ago

Solve for x.<br> 5x – 4 > 12 OR 12x+5 < -4

hammer [34]

Answer:

x < -3/4 OR x>16/5

Step-by-step explanation:

5x – 4 > 12 OR 12x+5 < -4

Solve the parts separately and then put back together

5x – 4 > 12

Add 4 to each side

5x-4+4>12+4

5x >16

Divide each side by 5

5x/5>16/5

x > 16/5

12x+5 < -4

Subtract 5 from each side

12x+5-5<-4-5

12x<-9

Divide each side by 12

12x<-9/12

x <-3/4

Put back together

x < -3/4 OR x>16/5

3 0

3 years ago

Determine which of the following statements is true for the function<br> g(x) = 415 - 3x + 24- 1.

Zarrin [17]

Answer:

?

Step-by-step explanation:

what are the statements??

4 0

3 years ago

A presidential candidate's aide estimates that, among all college students, the proportion who intend to vote in the upcoming el

inessss [21]

Answer:

$z=\frac{0.529 -0.6}{\sqrt{\frac{0.6(1-0.6)}{240}}}=-2.24$

$p_v =P(z$

If we compare the p value and the significance level given $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 1% of significance the proportion college students expressed an intent to vote is not higher than 0.6

Step-by-step explanation:

Assuming the following question: A presidential candidate's aide estimates that, among all college students, the proportion p who intend to vote in the upcoming election is at least 60% . If 127 out of a random sample of 240 college students expressed an intent to vote, can we reject the aide's estimate at the 0.1 level of significance?

Data given and notation

n=240 represent the random sample taken

X=127 represent the college students expressed an intent to vote

$\hat p=\frac{127}{240}=0.529$ estimated proportion of college students expressed an intent to vote

$p_o=0.6$ is the value that we want to test

$\alpha=0.01$ represent the significance level

Confidence=99% or 0.99

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that at least 60% of students are intented to vote .:

Null hypothesis: $p \geq 0.6$

Alternative hypothesis: $p < 0.6$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.529 -0.6}{\sqrt{\frac{0.6(1-0.6)}{240}}}=-2.24$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.01$ . The next step would be calculate the p value for this test.

Since is a left tailed test the p value would be:

$p_v =P(z$

If we compare the p value and the significance level given $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 1% of significance the proportion college students expressed an intent to vote is not higher than 0.6

7 0

3 years ago