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Likurg_2 [28]
3 years ago
9

Can you plz help me with this

Mathematics
1 answer:
stepan [7]3 years ago
5 0
The answer is probably (c).

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Find the equation of a line that passes through (5,-3) and is perpendicular to y = x.
VashaNatasha [74]
We know the slope is -1, because perpendicular line's slopes are always the negative reciprocal. We plug (5, -3) in to get:
-3 = -5 + b
b = 2
So we get C. y = -x + 2.
---
Hope this helps!
==jding713==
8 0
3 years ago
According to the Fundamental Theorem of Algebra, how many roots exist for the polynomial function f(x)=(4x3−13x+11)3?
trapecia [35]

Answer:

9.

Step-by-step explanation:

The highest power is 3*3 = 9, so it's 9.

7 0
2 years ago
Solve 1/p+1/s=1 for p
jekas [21]

Answer:

Step-by-step explanation:

Multiply through by the L. C. M which is PS.

1/p*ps+1/s*ps=1*ps

P+p=ps

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3 0
3 years ago
Factor the quadratic equation below to reveal the solutions. X^2+4x-21=-9
a_sh-v [17]

Answer:

x = 3 and x = -7

Step-by-step explanation:

The given quadratic equation is x^2+4x-21=0. We need to find the solution of this equation.

If the equation is in the form of ax^2+bx+c=0, then its solutions are given by :

x=\dfrac{-b\pm \sqrt{b^2-4ac} }{2a}

Here, a = 1, b = 4 and c = -21

Plugging all the values in the value of x, such that :

x=\dfrac{-b+ \sqrt{b^2-4ac} }{2a},\dfrac{-b- \sqrt{b^2-4ac} }{2a}\\\\x=\dfrac{-4+ \sqrt{(4)^2-4\times 1\times (-21)} }{2(1)},\dfrac{-4- \sqrt{(4)^2-4\times 1\times (-21)} }{2(1)}\\\\x=3, -7

So, the solutions of the quadratic equation are 3 and -7.      

6 0
3 years ago
Find an explicit formula for the following sequence, an, which starts with a1=7. 7,−14,28,−56,112,…
Digiron [165]

Answer:

simply multiply each number by -2

Step-by-step explanation:

7 * -2 = -14 -14 * -2

brainliest answer plz!

6 0
3 years ago
Read 2 more answers
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