So he used 0.33 L of milk to make 0.11 L of tea
Hi there!
PART A:
The system of equations we would use would be:
x + y = 22 (amount of items)
3x + 1y = 30 (cost)
Variables:
x = the amount of strawberry wafers bought at the price of $3
y = the amount of chocolate wafers bought at the price of $1
PART B:
To solve, we'll use substitution because we can easily isolate a variable using the first equation.
Work:
x + y = 22 (first equation)
y = 22 - x (isolating a variable)
3x + 1y = 30 (second equation)
3x + (22 - x) = 30 (substituting into the second equation)
2x + 22 = 30 (simplifying)
2x = 8 (subtracting)
x = 4 strawberry wafers
4 + y = 22 (substituting x into the first equation to solve for y)
y = 18 chocolate wafers
ANSWER:
They bought 4 strawberry wafers and 18 chocolate wafers.
Hope this helps!! :)
If there's anything else that I can help you with, please let me know!
I’m pretty sure the answer would be 116
The missing length is 51.5, I hope this helps :)
Answer:
f(x) = (x+2) (x+2)^3 (x-1) (x-6)
Step-by-step explanation:
The first zero, -2, corresponds to the factor x+2 of the polynomial.
Given that this zero, -2, has multiplicity 3, (x+2)^3 represent the first three factors of the polynomial.
The next factor stems from the zero 1: (x-1).
The next 6 factors stem from the zero 6: (x-6).
Writing the polynomial in factored form, we get:
f(x) = (x+2) (x+2)^3 (x-1) (x-6)
