All categories

3 years ago

9+10 equals 21 is correct 9+10 in roman numerals are true IX+X=XXI?

2 answers:

5 0

9+10=19 not 21
and in roman numerals IX+X equals IXX because if you put the "I" in front of the "X" it means that the number is 1 less than the value X ("X" in roman numerals equals 10 and "I" equals 1). Also if you put the "I" after the "X" it means that the value of that roman numeral is 1 more then "X".

Aleksandr [31]3 years ago

4 0

Not if you keep the ' l ' before the ' XX ' where it belongs. If it's before, then it means take the ' l ' away from them, and you get 19 just as you should. Now I understand this crazy question that keeps coming around.

You might be interested in

14 The straight line, L, has the equation y = 5 - 2x

diamong [38]

Answer:

When it crosses y-axis it means that x coordinate must be 0 so let substitute 0 to x, y=5-2*0

So coordinates are [0,5]

4 0

3 years ago

3(3b +2)=-30 what is b =

ycow [4]

3(3b+2)=-30 perform indicated multiplication on left side...

9b+6=-30 subtract 6 from both sides

9b=-36 divide both sides by 9

b=-4

4 0

3 years ago

Five-sixths of b is added to 7

Strike441 [17]

The answer would be 7+5/6b

5 0

3 years ago

Read 2 more answers

Which does not represent an integer?

miv72 [106K]

Answer:

The answer is D

Step-by-step explanation:

Let's see all choices in detail

A . 0 it is correct because 0 is an integer

B .It seems like rational number but it is not simplified yet so -18 \ 2= -9

C .

$\sqrt{9} = 3 \: so \: it \: is \: also \: integer$

D . 4\5 it is decimal so it is rational number not integer

I hope u like it

4 0

3 years ago

A restaurant sells about 330 sandwiches each day at a price of $6 each $.25 decrease in price. 15 more sandwiches are sold per d

zmey [24]

Answer:

restaurant should charge $(6-0.25) = $5.75per sandwich to maximize daily revenue.

the revenue is $1983.75

Step-by-step explanation:

to calculate current revenue= $6 x 330 = $1980

suppose x as the number of times the price to be dropped by $0.25

then find new price.. i.e

new price= $(6-0.25x)

and, new sell=330 +15x sandwiches

therefore, the new revenue would be= (6-0.25x)(330 +15x)

in order to maximize the current revenue, simplify the above equation and make it complete square using x

(6-0.25x)(330 +15x)

=1980-82.5x +90x -3.75 $x^{2}$

=1980 + 7.5x -3.75 $x^{2}$

=1980-3.75 (-2x+ $x^{2}$ ) ----> taking out common

now, to make a complete square lets add and subtract 1 inside the parentheses

=1980-3.75(-1+1-2x+ $x^{2}$ )

=1980 +3.75 -3.75( $x^{2}$ -2x +1)

=1983.75 -3.75 $(x-1)^{2}$ ---->(1)

as $(x-1)^{2}$ is positive always, minimize the other term in order to maximize the total revenue.

so the minimum possible value of $(x-1)^{2}$ = 0

therefore, x=1

putting x in eq(1) the revenure becomes,

$(1983.75-0)=> $1983.75

therefore, restaurant should charge $(6-0.25) = $5.75per sandwich to maximize daily revenue.

the revenue is $1983.75

3 0

3 years ago