3 years ago

Caitlyn did 6/7 of the problems on her math correctly and 4 incorrectly. She did all the problems. How many were there?

1 answer:

5 0

If $\frac{6}{7}$ were incorrect, it means that $\frac{1}{7}=4$ were correct
$4*7=28$
There were 28 problems ;)

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OlgaM077 [116]

Answer:

Sam is incorrect

Step-by-step explanation:

We can calculate the lengths of the diagonals using Pythagoras' identity.

The diagonals divide the rectangle and square into 2 right triangles.

Consider Δ SRQ from the rectangle

SQ² = SR² + RQ² = 12² + 6² = 144 + 36 = 180 ( take square root of both sides )

SQ = $\sqrt{180}$ ≈ 13.4 in ( to 1 dec. place )

Consider Δ ONM from the square

OM² = ON² + NM² = 6² + 6² = 36 + 36 = 72 ( take square root of both sides )

OM = $\sqrt{72}$ ≈ 8.5 in ( to 1 dec. place )

Now 2 × OM = 2 × 8.5 = 17 ≠ 13.4

Then diagonal OM is not twice the length of diagonal SQ

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3 years ago