Y(2)x(7)÷2
14 ÷2=7 I think
Hi,
To find weight of a single load you need to divide the weight (2/3 ton) with 4.
The weight of a single load is 0.165 ton.
Hope this helps.
r3t40
<em>p</em> … <em>q</em> … ¬<em>q</em> … <em>p</em> ∨ ¬<em>q</em> … (<em>p</em> ∨ ¬<em>q</em>) ⇒ <em>q</em>
T … T … F … T … T
T … F … T … T … F
F … T … F … F … T
F … F … T … T … F
Start with the first two columns, taking every possible pair of True/False for <em>p</em> and <em>q</em>.
¬<em>q</em> is just the negation of <em>q</em>, so True becomes False and False becomes True.
<em>p</em> ∨ <em>q</em> is the logical disjunction, or logical "or". It's True if either <em>p</em> or <em>q</em> is True, and False otherwise. So <em>p</em> ∨ ¬<em>q</em> is True only if either <em>p</em> or ¬<em>q</em> is True.
<em>p</em> ⇒ <em>q</em> is the logical implication. It's True only when both <em>p</em> and <em>q</em> are True, or when <em>p</em> is False. So (<em>p</em> ∨ ¬<em>q</em>) ⇒ <em>q</em> is True when both <em>p</em> ∨ ¬<em>q</em> and <em>q</em> are True, or when <em>p</em> ∨ ¬<em>q</em> is False.
let
x-------> the number of Lucy's orders
y-------> the number of Sam's orders
z-------> the number of Bob's orders
we know that
<u></u>----> equation A
-----> equation B
-----> equation C
substitute equation B and C in equation A
find z
find y
therefore
<u>the answer is</u>
the number of Lucy's orders is
the number of Sam's orders is
the number of Bob's orders is
Answer:
The probability that a randomly selected student has a score between 350 and 550 = 0.5867
Step-by-step explanation:
Mean = 500
Standard deviation = 110
Let X be the score of student in a standardized test
The probability that a randomly selected student has a score between 350 and 550 =
=
= Putting
=
= 0.6736 - .0869 ( Using Z table )
= 0.5867