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3 years ago

Help me (-: thank you

Mathematics

1 answer:

choli [55]3 years ago

7 0

15t + <35> j (price * count sold)

Cost = <4.5>t + 5 j + 150

Profilt = Revenue - Cost = (15t + <35>j) - (<4.5>t + 5j + 150)

= 15t + <35>j - <4.5>t < - >5j - 150
= 50t - -9.5j - 150

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How is 600:450 and 4:3 equalivent

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when you simplify 600:450 to the smallest it can be, its 4:3. For proof, multiply 4:3 by 150. 4 times 150 is 600 and 3 times 150 is 450.

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Solve y=2x2-3x-1 y=x-3

4vir4ik [10]

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Previous Question Question 14 of 20 Next Question A company randomly surveys 15 VIP customers and records their customer satisfa

Ann [662]

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71.4699, 81.7301.

Step-by-step explanation:

So, the following are the scores: 74

$Let,\;the\;total\;sum\;of\;the\;scores\;be:\sum x =1149$

$Then,\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\sum x^2=89795$

The length of the score : 15

Then, let the size of the scores be n : 15.

Then, we have to find the mean.

$\bar{x}=\frac{\sum x}{n}$

$=\frac{1149}{15}=76.6$

$Then,\;we\;have\;to\;find\;standard\;deviation:S=\sqrt{\frac{\sum x^2-n.(\bar{x})^2}{n-1} }$

$=\sqrt{\frac{89795-15\times(76.6)^2}{15-1} }=11.2808$

$The\;degree\;of\;freedom:n-1=14$

$So,\;the\;significant\;level:\alpha=1-0.90=0.10$

$and\;the\;critical\;value:t_{\frac{\alpha}{2} }=1.7613$

$Finally:\\=\bar{x}\;\pm\;t_{\frac{\alpha}{2} }\;\frac{S}{\sqrt{n} }\\=(71.4699, 81.7301)$

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3 years ago