Find the slope:
(-19 - 11) / (-8 - 2) = (-30/-10) = 3
Find the y intercept:
y = mx + b
11 = 3(2) + b
b= 5
So equation is:
y = 3x + 5
1.)
Old Number:35
New Number:45
Now, subract the new number(45) from the old number. (35)
45-35 is 10. Now divide the old number (35) by 10.
You'll get 3.5. 3.5%, increase is the answer for #1.
2.) Old: s (students)
New: 36,750
Do 100+5 (Addition because we do not know what the old number is.) 100+5 is 105. Move decimal over twice and you get 1.05. Multiply 36,750 by 1.05.
There were 38,587.5 kids last year.
3.)Since the discount is 15% off, do 100-15=85. Now, move the decimal over from the percent, and that makes that .85. Now multiply 50x.85. You get 42.5, or $42.50. Now the coupon is 10%, So subtract 100-10, giving you 90. Now move the decimal over. .90. Multiply 42.5 (or 42.50) by .90. You get 38.25. You do have enough money.
4.) Subtract 100-15, giving you 85. Move decimal over from percent. .85.
Now you would multiply .85 times k. B should be the answer.
I figured out the answer Chaseashley24! The answer to your question is:
0.673 m/s²
Hope this helps!
General Idea:
If we have a quadratic function of the form f(x)=ax^{2} +bx+c , then the function will attain its maximum value only if a < 0 & its maximum value will be at x=-\frac{b}{2a} .
Applying the concept:
The height h is modeled by h = −16t^2 + vt + c, where v is the initial velocity, and c is the beginning height of the firecracker above the ground. The firecracker is placed on the roof of a building of height 15 feet and is fired at an initial velocity of 100 feet per second. Substituting 15 for c and 100 for v, we get the function as 
.
Comparing the function f(x)=ax^{2} +bx+c with the given function 
, we get 
, 
and 
.
The maximum height of the soccer ball will occur at t=\frac{-b}{2a}=\frac{-100}{2(-16)} = \frac{-100}{-32}=3.125 seconds
The maximum height is found by substituting 
in the function as below:
Conclusion:
<u>Yes !</u> The firecracker reaches a height of 100 feet before it bursts.
Absolute value is always positive, unless there is a negative sign outside of the lines
