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katrin2010 [14]
2 years ago
12

Solve please. Correctly 3(1 - 2a) = -3a - 18

Mathematics
1 answer:
True [87]2 years ago
6 0

Answer:

a = 7

Step-by-step explanation:

3(1 - 2a) = -3a - 18

3 - 6a = - 3a - 18

Add 18 to each side:

3 + 18 - 6a = - 3a - 18 + 18

21 - 6a = - 3a

Add 6a to each side:

21 - 6a + 6a = - 3a + 6a

21 = 3a

3a = 21

Divide each side by 3:

3a ÷ 3 = 21 ÷ 3

a = 7

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The first day of Sam's vacation was a Monday. What day of the week was the Day 36 of Sam's vacation?
makvit [3.9K]

Answer:

A. Monday

Step-by-step explanation:

The solution to this problem can be found by creating a table

If Day 1 was Monday, then

Mon    Tues      Wed      Thur    Fri      Sat      Sun

1              2           3             4        5        6          7

8             9           10           11        12       13        14

...............

We can see that the multiples of 7 are falling on Sundays so we will divide 36 by 7 to get the closest multiple of 7 to 36.

The closest multiple of 7 near 36 is 35 so Day 35th will fall on Sunday and Day 36 will be on Monday

Hence, Option A is the correct answer..

3 0
3 years ago
the baker's at healthy Bakery can make 250 Bagels in the five hours how many bagels can they bake in 16 hours what was the rate
kolbaska11 [484]
Unit rate would be 50 because 250÷5=50, so the answer would be (250×3)+50, witch is 800.
3 0
3 years ago
What does x is greater than 5 mean
kotegsom [21]

Answer:

That  x is any number  bigger that 5 so 6 plus

Step-by-step explanation:

3 0
3 years ago
I'm confused on how to solve a right triangle given only one side measurement and one interior angle.
SVEN [57.7K]

Answer:

You use trigonometry.

Step-by-step explanation:

You can use soh cah toa. Basically you pic one side and if the interior angle is opposite or next to it, you you soh, or cah, or toa, it's based on where the angle is.

8 0
3 years ago
This is finding exact values of sin theta/2 and tan theta/2. I’m really confused and now don’t have a clue on how to do this, pl
Lostsunrise [7]

First,

tan(<em>θ</em>) = sin(<em>θ</em>) / cos(<em>θ</em>)

and given that 90° < <em>θ </em>< 180°, meaning <em>θ</em> lies in the second quadrant, we know that cos(<em>θ</em>) < 0. (We also then know the sign of sin(<em>θ</em>), but that won't be important.)

Dividing each part of the inequality by 2 tells us that 45° < <em>θ</em>/2 < 90°, so the half-angle falls in the first quadrant, which means both cos(<em>θ</em>/2) > 0 and sin(<em>θ</em>/2) > 0.

Now recall the half-angle identities,

cos²(<em>θ</em>/2) = (1 + cos(<em>θ</em>)) / 2

sin²(<em>θ</em>/2) = (1 - cos(<em>θ</em>)) / 2

and taking the positive square roots, we have

cos(<em>θ</em>/2) = √[(1 + cos(<em>θ</em>)) / 2]

sin(<em>θ</em>/2) = √[(1 - cos(<em>θ</em>)) / 2]

Then

tan(<em>θ</em>/2) = sin(<em>θ</em>/2) / cos(<em>θ</em>/2) = √[(1 - cos(<em>θ</em>)) / (1 + cos(<em>θ</em>))]

Notice how we don't need sin(<em>θ</em>) ?

Now, recall the Pythagorean identity:

cos²(<em>θ</em>) + sin²(<em>θ</em>) = 1

Dividing both sides by cos²(<em>θ</em>) gives

1 + tan²(<em>θ</em>) = 1/cos²(<em>θ</em>)

We know cos(<em>θ</em>) is negative, so solve for cos²(<em>θ</em>) and take the negative square root.

cos²(<em>θ</em>) = 1/(1 + tan²(<em>θ</em>))

cos(<em>θ</em>) = - 1/√[1 + tan²(<em>θ</em>)]

Plug in tan(<em>θ</em>) = - 12/5 and solve for cos(<em>θ</em>) :

cos(<em>θ</em>) = - 1/√[1 + (-12/5)²] = - 5/13

Finally, solve for sin(<em>θ</em>/2) and tan(<em>θ</em>/2) :

sin(<em>θ</em>/2) = √[(1 - (- 5/13)) / 2] = 3/√(13)

tan(<em>θ</em>/2) = √[(1 - (- 5/13)) / (1 + (- 5/13))] = 3/2

3 0
2 years ago
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