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katrin2010 [14]
2 years ago
12

Solve please. Correctly 3(1 - 2a) = -3a - 18

Mathematics
1 answer:
True [87]2 years ago
6 0

Answer:

a = 7

Step-by-step explanation:

3(1 - 2a) = -3a - 18

3 - 6a = - 3a - 18

Add 18 to each side:

3 + 18 - 6a = - 3a - 18 + 18

21 - 6a = - 3a

Add 6a to each side:

21 - 6a + 6a = - 3a + 6a

21 = 3a

3a = 21

Divide each side by 3:

3a ÷ 3 = 21 ÷ 3

a = 7

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1.
Harlamova29_29 [7]

Answer:

a) x = 1

Step-by-step explanation:

Given: 2x + 3 = 5

1. Subtract 3 from both sides:

2x + 3 - 3 = 5 - 3

⟹ 2x = 2

2. Divide both sides by 2:

2x ÷ 2 = 2 ÷ 2

⟹ x = 1

3. Check your work:

2(1) + 3 = 5

2 + 3 = 5

⟹ 5 = 5 ✔

Learn more about solving algebraic equations here:

brainly.com/question/27597890

brainly.com/question/25229258

8 0
2 years ago
Given a+b=7 and a–b=3, find: 2a·2b
nekit [7.7K]
I believe the answer is 40
5 0
2 years ago
Does there exist a di↵erentiable function g : [0, 1] R such that g'(x) = f(x) for all x 2 [0, 1]? Justify your answer
agasfer [191]

Answer:

No; Because g'(0) ≠ g'(1), i.e. 0≠2, then this function is not differentiable for g:[0,1]→R

Step-by-step explanation:

Assuming:  the function is f(x)=x^{2} in [0,1]

And rewriting it for the sake of clarity:

Does there exist a differentiable function g : [0, 1] →R such that g'(x) = f(x) for all g(x)=x² ∈ [0, 1]? Justify your answer

1) A function is considered to be differentiable if, and only if  both derivatives (right and left ones) do exist and have the same value. In this case, for the Domain [0,1]:

g'(0)=g'(1)

2) Examining it, the Domain for this set is smaller than the Real Set, since it is [0,1]

The limit to the left

g(x)=x^{2}\\g'(x)=2x\\ g'(0)=2(0) \Rightarrow g'(0)=0

g(x)=x^{2}\\g'(x)=2x\\ g'(1)=2(1) \Rightarrow g'(1)=2

g'(x)=f(x) then g'(0)=f(0) and g'(1)=f(1)

3) Since g'(0) ≠ g'(1), i.e. 0≠2, then this function is not differentiable for g:[0,1]→R

Because this is the same as to calculate the limit from the left and right side, of g(x).

f'(c)=\lim_{x\rightarrow c}\left [\frac{f(b)-f(a)}{b-a} \right ]\\\\g'(0)=\lim_{x\rightarrow 0}\left [\frac{g(b)-g(a)}{b-a} \right ]\\\\g'(1)=\lim_{x\rightarrow 1}\left [\frac{g(b)-g(a)}{b-a} \right ]

This is what the Bilateral Theorem says:

\lim_{x\rightarrow c^{-}}f(x)=L\Leftrightarrow \lim_{x\rightarrow c^{+}}f(x)=L\:and\:\lim_{x\rightarrow c^{-}}f(x)=L

4 0
3 years ago
Write this whole number as a product of prime numbers.<br><br> 50
Lostsunrise [7]

Answer:

Prime factorization: 50 = 2 x 5 x 5

8 0
3 years ago
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Which statement best describes the area of the triangle shown below?
cupoosta [38]
It is 4x4 then divide that by 2 since a triangle is half of a square so 16 divided by 2 which is 8
7 0
2 years ago
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