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erma4kov [3.2K]
4 years ago
10

Giving brainiest+points need explanation on this one my answer is 25 is it right?

Mathematics
1 answer:
Sergio [31]4 years ago
4 0
Yes, the answer of 25 is correct.

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Help me
Nutka1998 [239]

Answer:

Step-by-step explanation:

x + (x + 2) + (x+4) =12

3x + 6 = 12

3x = 6

x = 2

7 0
3 years ago
Eric buys cheese from the local farmer's market. The graph below shows the cheese cost (in cents) versus its weight (in
sesenic [268]

Answer:

i cant see the whole thing

Step-by-step explanation:

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3 years ago
A math test is worth 100 points and has 30 problems. Each problem is worth either 3 points or 4 points. How many 4-point problem
LiRa [457]
I think there's 24 4-point probs
6 0
3 years ago
Please can someone help me on this question ?!!!!!!!!!!!I WILL MARK BRIANLIEST
igor_vitrenko [27]

Answer:

Step-by-step explanation:

This doesn’t make sense

3 0
3 years ago
a university received 9 applications for three postdoctorate fellowships. five of the applicants are men and four are women. fin
frozen [14]

There are 9C_3 ways to select 3 from 9.

There are 5C_3 ways to select 3 men from 5 men and 4C_3 ways to select 3 women from 4 women.



If all three selected are men, then no woman was selected, and we have

5C_3 \times 4C_0 ways we can do that.



1)



P(All -3 -are -men)=[tex]\frac{5C_3 \times 4C_0}{9C_3}=\frac{5}{42}





2) If all 3 are women then no man was selected, and we have

5C_0 \times 4C_3 ways we can do that.


P(All- 3- are- women)=\frac{5C_0 \times 4C_3}{9C_3}=\frac{1}{21}



3) If 2 men and 1 woman were selected, the we have 5C_2\times 4C_1 ways we can do that.


P(2 -men -1 -woman)=\frac{5C_2\times 4C_1}{9C_3}=\frac{10}{21}




4) If 2 women and 1 man is selected, then we have  5C_1 \times 4C_2

P(2- women- 1 -man)=\frac{5C_1\times 4C_2}{9C_3}=\frac{5}{14}



8 0
4 years ago
Read 2 more answers
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