Ask question

Ask question

All categories

2 years ago

14

Find the common ratio for the following sequence. 0.1, 0.01, 0.001, ... 0.01 0.1 0.001

1 answer:

Zinaida [17]2 years ago

5 0

Answer:

$\frac{1}{10}$

Step-by-step explanation:

$a_1 = 0.1\\a_2 = 0.01\\a_3 = 0.001$

$r = \frac{a_2}{a_1}$

$r = \frac{0.01}{0.1}$

$r=0.1$

You might be interested in

Number 2 , answer ? I don’t know the answer and I need help

snow_tiger [21]

Answer:

it's B

Step-by-step explanation:

because you just add those but before you do that you have to divide the fractions like for example 1/2=.5 so you add the .5 to 8 so 8.5 . And you keep doing that with the other ones that also have fractions and then once you're done doing that you add all your four numbers

8 0

2 years ago

I 1/4 greater or less than 1/2

tangare [24]

1 1/4 is greater than 1/2

There are 5- 1/4's in 1 1/4
There are 2- 1/4's in 1/2

7 0

2 years ago

Please help !!!! I want to pass

inna [77]

Answer:

51.3

Step-by-step explanation:

I will upload a photo soon, but it is from trig, and inverse cos.

6 0

3 years ago

V = πrh (solve for h)

Mila [183]

Answer:

H=V/pi(r)

Step-by-step explanation:

You divide by pi and r...

V/pi(r)=h

7 0

3 years ago

Your school’s baseball team sells 1250 raffle tickets at $4 each. The grand prize is a $3000 boat. The second prize is a $450 gr

densk [106]

Answer:

The expected value of the winnings for a single-ticket purchase is -$1.0016.

Step-by-step explanation:

The total number of tickets sold is, <em>N</em> = 1250.

Cost of one ticket is, $4.

Let <em>X</em> = amount of prize.

The prize distribution is as follows:

1 Grand price = $3000

1 Second prize = $450

10 Third prize = $25

The expected value <em>X</em> can be computed using the formula:

$E(X)=\sum x.P(X)$

Compute the probability distribution of <em>X</em> as follows:

Prize Amount (X) P (X) x · P (X)

1 Grand prize $3000 $\frac{1}{1250}=0.0008$ $\$3000\times 0.0008=2.4$

1 Second prize $450 $\frac{1}{1249}=0.0008$ $\$450\times 0.0008=0.36$

10 Third prize $25 $\frac{10}{1248}=0.008$ $\$25\times 0.008=0.2$

No prize -$4 $1-\sum P(Win)\\=0.9904$ $-\$4\times 0.9904=-3.9616$

TOTAL 1.0000 -1.0016

Thus, the expected value of the winnings for a single-ticket purchase is -$1.0016.

5 0

2 years ago