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ANTONII [103]
3 years ago
13

A juice box is 2 inches long 1.5 inches and 4 inches tall. A package has 6 juice boxes, a shipping box holds exactly 24 packages

of juice boxes. What is the volume of the shipping box
Mathematics
1 answer:
Westkost [7]3 years ago
8 0

Answer:

V=1,728\ in^3

Step-by-step explanation:

step 1

Find the volume of one juice box

The volume is equal to

V=LWH

where

L=2\ in\\W=1.5\ in\\H=4\ in

substitute the values in the formula

V=(2)(1.5)(4)

V=12\ in^3

step 2

Find the volume of one package

we know that

A package has 6 juice box

so

Multiply the volume of one juice box by 6

V=6(12)=72\ in^3

step 3

Find the volume of the shipping box

we know that

A shipping box holds exactly 24 packages of juice boxes

Multiply the volume of one package by 24

V=24(72)=1,728\ in^3

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3x - 20 = 4 PLEASE EXPLAIN HOW YOU GOT THE ANSWER IN STEPS!
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Answer:

x = 8

Step-by-step explanation:

3x - 20 = 4

add 20 to both sides

3x - 20 + 20 = 4 + 20

3x = 24

divide both sides by 3

\frac{3x}{3} = \frac{24}{3}

x = 8

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Which statement is true about whether A and B are independent events? A and B are independent events because P(A∣B) = P(A) = 0.1
love history [14]
The events A and B are independent if the  probability that event A occurs does not affect the probability that event B occurs.
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Conditional probability is the probability of an event given that some other event first occurs.
P(B|A)=P(A∩B)/P(A)
In the case where events<span> A and B are </span>independent<span> the </span>conditional probability<span> of </span>event<span> B given </span>event<span> A is simply the </span>probability<span> of </span>event<span> B, that is P(B).</span>
Statement 1:A and B are independent events because P(A∣B) = P(A) = 0.12. This is true.
Statement 2:<span>A and B are independent events because P(A∣B) = P(A) = 0.25.
This is true.
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5 0
3 years ago
Read 2 more answers
What is the standard form of the equation of a line for which the length of the normal segment to the origin is 8 and the normal
jeka57 [31]
Slope of line = tan(120) = -tan(60) = - &radic;3
Distance from origin = 8

Let equation be Ax+By+C=0
then -A/B=-&radic;3, or
B=A/&radic;3.
Equation becomes
Ax+(A/&radic;3)y+C=0

Knowing that line is 8 units from origin, apply distance formula
8=abs((Ax+(A/&radic;3)y+C)/sqrt(A^2+(A/&radic;3)^2))
Substitute coordinates of origin (x,y)=(0,0)  =>
8=abs(C/sqrt(A^2+A^2/3))
Let A=1 (or any other arbitrary finite value)
solve for positive solution of C
8=C/&radic;(4/3) => C=8*2/&radic;3 = (16/3)&radic;3

Therefore one solution is
x+(1/&radic;3)+(16/3)&radic;3=0
or equivalently
&radic;3 x + y + 16 = 0

Check:
slope = -1/&radic;3  .....ok
distance from origin
= (&radic;3 * 0 + 0 + 16)/(sqrt(&radic;3)^2+1^2)
=16/2
=8  ok.

Similarly C=-16 will satisfy the given conditions.

Answer  The required equations are
&radic;3 x + y = &pm; 16 
in standard form.

You can conveniently convert to point-slope form if you wish.




4 0
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