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RSB [31]
3 years ago
6

Can someone help plz ​

Mathematics
1 answer:
steposvetlana [31]3 years ago
5 0
Subtract it and you will find your answer hope this helps
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Find a factorization of x² + 2x³ + 7x² - 6x + 44, given that<br> −2+i√√7 and 1 - i√/3 are roots.
Levart [38]

A factorization of x^4+2x^3+7x^2-6x+44 is (x^2+4x+11)(x^2-2x+4).

<h3>What are the properties of roots of a polynomial?</h3>
  • The maximum number of roots of a polynomial of degree n is n.
  • For a polynomial with real coefficients, the roots can be real or complex.
  • The complex roots of a polynomial with real coefficients always exist in a pair of conjugate numbers i.e., if a+ib is a root, then a-ib is also a root.

If the roots of the polynomial p(x)=ax^4+bx^3+cx^2+dx+e are r_1,r_2,r_3,r_4, then it can be factorized as p(x)=(x-r_1)(x-r_2)(x-r_3)(x-r_4).

Here, we are to find a factorization of p(x)=x^4+2x^3+7x^2-6x+44. Also, given that -2+i\sqrt{7} and 1-i\sqrt{3} are roots of the polynomial.

Since p(x)=x^4+2x^3+7x^2-6x+44 is a polynomial with real coefficients, so each complex root exists in a pair of conjugates.

Hence, -2-i\sqrt{7} and 1+i\sqrt{3} are also roots of the given polynomial.

Thus, all the four roots of the polynomial p(x)=x^4+2x^3+7x^2-6x+44, are: r_1=-2+i\sqrt{7}, r_2=-2-i\sqrt{7}, r_3=1-i\sqrt{3}, r_4=1+i\sqrt{3}.

So, the polynomial p(x)=x^4+2x^3+7x^2-6x+44 can be factorized as follows:

\{x-(-2+i\sqrt{7})\}\{x-(-2-i\sqrt{7})\}\{x-(1-i\sqrt{3})\}\{x-(1+i\sqrt{3})\}\\=(x+2-i\sqrt{7})(x+2+i\sqrt{7})(x-1+i\sqrt{3})(x-1-i\sqrt{3})\\=\{(x+2)^2+7\}\{(x-1)^2+3\}\hspace{1cm} [\because (a+b)(a-b)=a^2-b^2]\\=(x^2+4x+4+7)(x^2-2x+1+3)\\=(x^2+4x+11)(x^2-2x+4)

Therefore, a factorization of x^4+2x^3+7x^2-6x+44 is (x^2+4x+11)(x^2-2x+4).

To know more about factorization, refer: brainly.com/question/25829061

#SPJ9

3 0
1 year ago
Read 2 more answers
PLS HELP IM BEGGING U
expeople1 [14]

Answer:

answer is 57.

Step-by-step explanation:

Given

m<6= x - 8

m<7 = 2x - 7

We know

<6 + <7 = 180° [ being linear pair ]

x - 8 + 2x - 7 = 180°

3x - 15 = 180°

3x = 180° + 15°

3x = 195°

x = 195° / 3

x = 65°

Now

m<6= x - 8 = 65° - 8° = 57°

hope it helps :)

8 0
3 years ago
Find the slope for<br> 6y-10x=30
Nuetrik [128]
Slope intercept form is y=5/3x+5
The slope is 5/3
8 0
2 years ago
Read 2 more answers
If Javier has a car with a mass of 250,000 kg and it is acted upon with a force of 300 Newtons. What is the acceleration?
natima [27]

Answer:

<u>The acceleration is 0.0012 meters/seconds²</u>

Step-by-step explanation:

1. Let's review the information given to answer the question correctly:

Mass = 250,000 kg

Force = 300 Newtons

2. What is the acceleration?

Based on Newton's Second Law of Motion, let's recall that:

Force = Mass * Acceleration

Acceleration = Force/Mass

Replacing with the real values, we have:

Acceleration = 300/250,0000

Acceleration = 0.0012 meters/seconds² (we can't express acceleration using Newtons/kilograms as the unit).

8 0
3 years ago
Suppose y varies inversely as x, and y = 16 when x = 1/2. Find y when x = 17.
MArishka [77]

<u>Finding the proportionality constant</u> :

  • y = k/x
  • 16 = k/(1/2)
  • <u>k = 8</u>

<u>Finding y when x = 17</u> :

  • y = 8/(17)
  • y = 8/17

The value of y is <u>8/17</u> when x = 17.

5 0
2 years ago
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