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slega [8]
4 years ago
13

Quiz

Mathematics
1 answer:
valina [46]4 years ago
4 0

Answer:

Step-by-step explanation:

As we know that in an hour there are 3600 seconds so

1.8 x 3600 = 6480

 6480 / 1609 = 4.02 miles / hr

  4.02 - 2.5 = 1.5( by substracting the speed)

so correct option is D which is

 Talia swims about 1.5 miles per hour faster than Alina

hope it helps

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Answer the following question for a chance of
mr Goodwill [35]

Answer:

i believe it is 2.0983

Step-by-step explanation:

I just tried to make a possible answer

8 0
3 years ago
A and B are complementary angles. If mA=(x+8)° and mB =(8x+1),<br> find the measure of A
Black_prince [1.1K]

Answer:

\angle A=17\textdegree

Step-by-step explanation:

We know that A and B are complementary angles. So, they must add up to 90°. As an equation:

\angle A+\angle B=90

Since we know their equations, substitute:

(x+8)+(8x+1)=90

Solve for x. Combine like terms on the left:

9x+9=90

Subtract 9 from both sides:

9x=81

Divide both sides by 9:

x=9

So, the value of x is 9.

We want to find A. So, let's use the equation for A:

\angle A=x+8

Substitute 9 for x:

\angle A=9+8

Add:

\angle A=17\textdegree

So, the measure of A is 17°.

4 0
3 years ago
Yesterday, a movie theater sold 299 bags of popcorn. A large bag of popcorn costs $4. A small bag of popcorn costs $1. In all, t
dem82 [27]

Answer:

Step-by-step explanation:

They sold 201 small bags

and they sold 83 large bags

hope this helps :)

6 0
3 years ago
Read 2 more answers
A theatre has 50 seats on the front row. There are 4 additional seats in each following row.
alexandr402 [8]
\boxed { \boxed { T_n = a_1 + d(n - 1)}}

\text {Given that }a_1 = 50 \text { and } d = 4

T_n = 50 + 4(n - 1)

T_n = 50 + 4n - 4

T_n = 46 + 4n

\boxed { \boxed {T_n = 46 + 4n }}

When n = 20,
T_{20} = 46 + 4(20) = 126

\boxed { \boxed {\text{Answer: The 20th term is 126}}}
4 0
3 years ago
A trough has ends shaped like isosceles triangles, with width 5 m and height 7 m, and the trough is 12 m long. Water is being pu
Svet_ta [14]

Answer:

\dfrac{dh}{dt}=21 \text{m/min}

the rate of change of height when the water is 1 meter deep is 21 m/min

Step-by-step explanation:

First we need to find the volume of the trough given its dimensions and shape: (it has a prism shape so we can directly use that formula OR we can multiply the area of its triangular face with the length of the trough)

V = \dfrac{1}{2}(bh)\times L

here L is a constant since that won't change as the water is being filled in the trough, however 'b' and 'h' will be changing. The equation has two independent variables and we need to convert this equation so it is only dependent on 'h' (the height of the water).

As its an isosceles triangle we can find a relationship between b and h. the ratio between the b and h will be always be the same:

\dfrac{b}{h} = \dfrac{5}{7}

b=\dfrac{5}{7}h this can be substituted back in the volume equation

V = \dfrac{5}{14}h^2L

the rate of the water flowing in is:

\dfrac{dV}{dt} = 6

The question is asking for the rate of change of height (m/min) hence that can be denoted as: \frac{dh}{dt}

Using the chainrule:

\dfrac{dh}{dt}=\dfrac{dh}{dV}\times \dfrac{dV}{dt}

the only thing missing in this equation is dh/dV which can be easily obtained by differentiating the volume equation with respect to h

V = \dfrac{5}{14}h^2L

\dfrac{dV}{dh} = \dfrac{5}{7}hL

reciprocating

\dfrac{dh}{dV} = \dfrac{7}{5hL}

plugging everything in the chain rule equation:

\dfrac{dh}{dt}=\dfrac{dh}{dV}\times \dfrac{dV}{dt}

\dfrac{dh}{dt}=\dfrac{7}{5hL}\times 6

\dfrac{dh}{dt}=\dfrac{42}{5hL}

L = 12, and h = 1 (when the water is 1m deep)

\dfrac{dh}{dt}=\dfrac{42}{5(1)(12)}

\dfrac{dh}{dt}=21 \text{m/min}

the rate of change of height when the water is 1 meter deep is 21 m/min

6 0
3 years ago
Read 2 more answers
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