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3 years ago

11

The zoo needed to raise 25000.zoo officials planned a dinner/dance event and charged $300 per couple. What is the fewest number

of people that would need to attend in order for the goal to b met

2 answers:

garri49 [273]3 years ago

6 0

83.3333333 is the answer rounded to 83

BabaBlast [244]3 years ago

6 0

They would need 8334 couples to come. You get this number by dividing 25000 by 300.

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Ratio 400g : 1kg can be written in the form 1 : n find the value of n?

zvonat [6]

400 : 1kg
400 : 1000
1 : 2.5

n = 2.5

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2 years ago

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ElenaW [278]

Answer:

Here,

x + 25° + 3x + 95° + 80°=360° (Sum of angles of a quadrilateral is 360°)

or,x+3x + 25° + 95° + 80° =360°

or,4x + 200 = 360°

or,4x = 360 - 200

or,4x = 160

or,x = 160÷4

or,x = 40

Now,

Angle K = (x + 25)° = 40 + 25° = 65°

Angle L = 3x° = 3 × 40° = 120°

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2 years ago

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Answer:

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Step-by-step explanation:

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2 years ago

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A ladder is leaning up against a house. The ladder is 20 feet long and the base of the ladder is 12 feet away from the house. Ho

MrRa [10]

Answer:

16 feet

Step-by-step explanation:

The length of the ladder=20 feet

Distance from the base of the ladder to the house = 12 feet

You will notice that a wall is vertical and the ladder makes an angle with the horizontal ground(making it the hypotenuse). This is a right triangle problem.

To find the how far up the house can the ladder can reach, we simply find the third side of the right triangle.

From Pythagoras theorem

$Hyp^2=Opp^2+Adj^2\\20^2=12^2+Adj^2\\Adj^2=400-144\\Adj^2=256\\Adj=\sqrt{256}=16$

The third side of the right triangle is 16. Therefore the ladder leans 16 feet from the ground.

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3 years ago

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Solve each system of equations; nonlinear algebra 2<br><br> x2 + x + y - 26 = 0<br> x + y = 1

BigorU [14]

Answer:

(5,-4) and (-5,6)

Step-by-step explanation:

Given:

$\left\{\begin{array}{l}x^2+x+y-26=0\\ \\x+y=1\end{array}\right.$

Solve it. First, express y in terms of x from the second equation:

$y=1-x$

Substitute it into the first equation:

$x^2+x+1-x-26=0\\ \\x^2-25=0\\ \\(x-5)(x+5)=0$

Apply zero product property:

$x-5=0\ \text{or}\ x+5=0$

So,

$x=5\ \text{or}\ x=-5$

When $x=5,$ then $y=1-5=-4$

When $x=-5,$ then $y=1-(-5)=6$

We get two solutions: (5,-4) and (-5,6)

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3 years ago