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kondor19780726 [428]
3 years ago
9

Ignacio wants to build a bigger toy box for his cousins. Their current toy box has dimensions of 24 inches by 18 inches by 18 in

ches. What happens to the volume of the toy box if he doubles each dimension?
Mathematics
1 answer:
Ber [7]3 years ago
4 0
The volume (V) of the box is the product when we multiply the length (L) with the width (W) and with the height (H). The equation is, 
                                     V = L x W x H
If we double each dimension, the volume becomes (2L) x (2W) x (2H) = 8 L x W x H. This is equivalent 8V. Thus, the volume is multiplied by 8. 
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When putting a number into scientific notation, the number you use must be between what two numbers?
Goshia [24]

Answer:

1 and 10

Step-by-step explanation:

can't be less than 1 but can't be more than 10

4 0
3 years ago
Henry located 2 1/4 and 2.1 on a number line. He wrote the following related story:
Rzqust [24]

Answer:

Jerry ran a farther distance and not Henry.

Step-by-step explanation:

We are given the following information in the question:

Jerry rain 2\frac{1}{2} miles and Henry ran 2.1 miles.

Henry claimed that he ran a farther distance.

This is a wrong claim because when we compare:

2\frac{1}{2} and 2.1

2\displaystyle\frac{1}{2} = \displaystyle\frac{5}{2} = 2 + 0.5 = 2.5\\\\2.5 > 2.1

Hence, Jerry ran a farther distance and not Henry.

Henry may have made some mistake in plotting   2\frac{1}{2} and 2.1 on the number line.

4 0
3 years ago
Which algebraic expression represents the phrase "seven more than half of a number"?
Igoryamba

Answer:

i believe it is the first answer.

Step-by-step explanation:

3 0
3 years ago
Please help i’m so stuck i can’t do calc for the life of me
KATRIN_1 [288]

Answer:

-3x^2+29x-150+\frac{946x^2-341x-756}{x^3+6x^2-3x-5}  is the answer. See steps below.

Step-by-step explanation:

\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}\\\\-3x^5+11x^4+33x^3-26x^2-36x-6\\\\\mathrm{and\:the\:divisor\:}x^3+6x^2-3x-5:\\\\\mathrm{Quotient}=\frac{-3x^5}{x^3}=-3x^2\\\\\mathrm{Multiply\:}x^3+6x^2-3x-5\mathrm{\:by\:}-3x^2\:\:\rightarrow\:\:-3x^5-18x^4+9x^3+15x^2\\\\\mathrm{Subtract\:}-3x^5-18x^4+9x^3+15x^2\mathrm{\:from\:}-3x^5+11x^4+33x^3-26x^2-36x-6\mathrm{\:to\:get\:new\:remainder}.\\\\\mathrm{Remainder}=29x^4+24x^3-41x^2-36x-6

=-3x^2+\frac{29x^4+24x^3-41x^2-36x-6}{x^3+6x^2-3x-5}

Repeat the steps and you will reach a point where no further division is possible.

<u />

<u />=-3x^2+29x-150+\frac{946x^2-341x-756}{x^3+6x^2-3x-5}<u />

5 0
3 years ago
What are two ratios that are equivalent to 27:9
skad [1K]
For this case we have the following relationship:
 27:9
 To find two equivalent relationships, what we must do is divide both numbers by a number that is multiple of both.
 We then have to divide by three:
 9:3
 Then, dividing again between three we have:
 3:1
 Answer:
 two ratios that are equivalent to 27:9 are:
 Ratio 1:
 9:3
 Ratio 2:
 3:1
3 0
3 years ago
Read 2 more answers
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