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3 years ago

6

How many solutions 2x+4=2(x+2) 0 1 many

1 answer:

AleksandrR [38]3 years ago

6 0

In order to find the number of solutions, we first must solve the equation.

2x+4=2x+4
2x=2x
x=x

When x=x, we can use infinetly many solutions. For example if we try the value x=4, we can input it into the equation.

2(4)+4=2((4)+2)
8+4=2(6)
12=12

Since we got an answer that is true, we can say confidently there are one solutions. This remains true for all real values of x.

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Answer:

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Step-by-step explanation:

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3 years ago

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aleksandr82 [10.1K]

Using the normal distribution, the probabilities are given as follows:

a. 0.4602 = 46.02%.

b. 0.281 = 28.1%.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean $\mu$ and standard deviation $\sigma$ is given by:

$Z = \frac{X - \mu}{\sigma}$

The z-score measures how many standard deviations the measure is above or below the mean.

Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

The parameters are given as follows:

$\mu = 959, \sigma = 263, n = 37, s = \frac{263}{\sqrt{37}} = 43.24$

Item a:

The probability is <u>one subtracted by the p-value of Z when X = 984</u>, hence:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{984 - 959}{263}$

Z = 0.1

Z = 0.1 has a p-value of 0.5398.

1 - 0.5398 = 0.4602.

Item b:

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem:

$Z = \frac{X - \mu}{s}$

$Z = \frac{984 - 959}{43.24}$

Z = 0.58

Z = 0.58 has a p-value of 0.7190.

1 - 0.719 = 0.281.

More can be learned about the normal distribution at brainly.com/question/4079902

#SPJ1

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