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iren [92.7K]
3 years ago
9

Which of the following describes the end behavior over the domain of the square root function graphed above? Please HELP!!!!!!!!

! MARK THE BRAINLEST

Mathematics
1 answer:
PilotLPTM [1.2K]3 years ago
8 0
Short Answer A
Comment

It's a good thing that the domain is confined or the graph is. That function is undefined if x < - 3 

At exactly x = - 3, f(x) = 0 and that's your starting point.

So look what happens to this graph. If x = 0, f(0) =  y = 3. So we are starting to see that as x get's larger so does f(x). The graph tells us that x = 0 is bigger than x = - 3.

Let's keep on plugging things in.
As x increases to 5, f(5) = 5. x = 5 is larger than x = 0, and f(5) > 3.

One more and then we'll start drawing conclusions. If x = 9 then f(9) = y =  6. 
x = 9 is larger than x = 5. f(9) = 6 is just larger than f(5) which is 5

OK I think we should be ready to look at answers. There's nothing there that makes the answer anything but a. Let's find out what the problem is with the rest of the choices.

B
The problem with B is that as x increases, f(x) does not decrease. We didn't find one example of that. So B is wrong.

C
C has exactly the same problem as B. 

D
The second statement in D is incorrect. As x increases f(x) never decreases. No example showed that.

The answer is A <<<< Answer.
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108 ft²

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Increasing by 50% means multiplying the original quantities by 1.5, that is

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new width = 1.5 × 6 ft = 9 ft

Thus

Area = length × width = 12 × 9 = 108 ft²

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Suppose a population of honey bees in Ephraim, UT has an initial population of 2300 and 12 years later the population reaches 13
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Answer:

common ratio: 1.155

rate of growth: 15.5 %

Step-by-step explanation:

The model for exponential growth of population P looks like: P(t)=P_i(1+r)^t

where P(t) is the population at time "t",

P_i is the initial (starting) population

(1+r) is the common ratio,

and r is the rate of growth

Therefore, in our case we can replace specific values in this expression (including population after 12 years, and  initial population), and solve for the unknown common ratio and its related rate of growth:

P(t)=P_i(1+r)^t\\13000=2300*(1+r)^{12}\\\frac{13000}{2300} = (1+r)^12\\\frac{130}{23} = (1+r)^{12}\\1+r=\sqrt[12]{\frac{130}{23} } =1.155273\\

This (1+r) is the common ratio, that we are asked to round to the nearest thousandth, so we use: 1.155

We are also asked to find the rate of increase (r), and to express it in percent form. Therefore we use the last equation shown above to solve for "r" and express tin percent form:

1+r=1.155273\\r=1.155273-1=0.155273

So, this number in percent form (and rounded to the nearest tenth as requested) is: 15.5 %

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