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Amanda [17]
3 years ago
11

I need help with number 6c

Mathematics
1 answer:
Ugo [173]3 years ago
3 0

Remark

Let's assume that each square consists of 4 matchsticks. If this is incorrect, leave a note. We can't really see how many match sticks make up a square, so it makes 6c hard.

Solution

First write the number of squares in the nth windmill.

d = 4 (that's derived from 13 - 9 which are the second and third term.

n = n

a = 5

an = a + (n - 1)*d

an = 5 + (n - 1)*4

Now each square is made up of 4 matchsticks.

So you need to multiply "an" by 4 to get the number of matchsticks.

an_match = 4*[5 + (n -1)*4]         Remove the inner brackets

an_match = 4*[5 + 4n - 4]

an_match = 4*[4n - 1]     Remove the square brackets.

an_match = 16n  - 4  <<<< Answer

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PLEASE HELP! Will give brainliest! A bag contains 5 pink marbles and 6 green marbles. Two marbles will be selected one at a time
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Answer:

The selection of the two marbles are <u>dependent</u> because the selection of the pink marble <u>changes</u> the probability that a green marble is drawn next.

If the pink marble had been put back into the bag, the selection of the two marbles would have been <u>independent</u>

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Explanation:

The key phrase to focus on here is "This marble is placed on a table". It implies that we do not put it back into the bag, and also implies we don't put in a replacement either. Hence we consider this scenario as "no replacement".

In no replacement situations, we always have dependent events. The second selection depends on the first one.

The probability of picking green is 6/11 because there are 6 green out of 5+6 = 11 total. But if we picked a pink one first and didn't put it back, then the 11 drops to 10 and we get 6/10 = 3/5 as the new probability.

In other words,

  • before the pink marble is selected, the chances of green are 6/11
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Because this probability changes, it's sufficient evidence to say the event of picking green on the second selection is dependent on the first selection of selecting pink.

If the marble had been put back, then we'd revert back to the original state of the bag. That would mean the chances of green would stay at 6/11. Therefore, situations with replacement lead to independent events.

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