The unit rate is 60 miles per hour and the driver will reach before time with the calculated constant speed
Step-by-step explanation:
Given
Distance = d = 45 miles
Time = t = 3/4 hour
The unit rate is defined as the distance per unit time. In this case, the unit rate can also be called speed.
So,

Using this unit rate we can see if the car can travel 65 miles in 1.25 hours or not
Given
Distance = d1 = 65 miles
Speed = s = 60 miles per hour
Putting the values in the formula for speed

As we can see that 1.08 is less than 1.25 so the driver will reach the meeting before time if he drives on a constant speed of 60 miles per hour
Hence,
The unit rate is 60 miles per hour and the driver will reach before time with the calculated constant speed
Keywords: Speed, unit rate
Learn more about speed at:
#LearnwithBrainly
Answer:
check the length and the angles and check the height of it
Answer:
2over1 multiply by 6over 3then you devide both sides by the given numbers then answer is 6woal number 1out of 6
Since ZY bisects GE and XY bisects EF, and both ZY and XY both bisect GF, then XY ~ ZE and ZY ~ XE.
Therefore ZE = XY = 5
And GE = 2× ZE (because bisected segments are = and therefore ×2 = long segment).
So GE = 2ZE = 2×5 = 10
Answer:
Here's what I get.
Step-by-step explanation:
1. Representation of data
I used Excel to create a scatterplot of the data, draw the line of best fit, and print the regression equation.
2. Line of best fit
(a) Variables
I chose arm span as the dependent variable (y-axis) and height as the independent variable (x-axis).
It seems to me that arm span depends on your height rather than the other way around.
(b) Regression equation
The calculation is easy but tedious, so I asked Excel to do it.
For the equation y = ax + b, the formulas are

This gave the regression equation:
y = 1.0595x - 4.1524
(c) Interpretation
The line shows how arm span depends on height.
The slope of the line says that arm span increases about 6 % faster than height.
The y-intercept is -4. If your height is zero, your arm length is -4 in (both are impossible).
(d) Residuals

The residuals appear to be evenly distributed above and below the predicted values.
A graph of all the residuals confirms this observation.
The equation usually predicts arm span to within 4 in.
(e) Predictions
(i) Height of person with 66 in arm span

(ii) Arm span of 74 in tall person
