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2 years ago

Please help me fast i am giving 14 points for 5 questions. (Geometry) Thank you so much!

1 answer:

algol132 years ago

6 0

1 ) Area of the rectangle:
A = L x W
L = √(2² + 2²) = √8 = 2√2
W = √(6² + 6²) = √72 = 6√2
A = 2√2 x 6√2 = 24 units²
2 ) Area of a triangle:
RQ = 2 + 4 = 6 units
h = 4 units
A = ( 6 * 4 ) / 2 = 12 units²
3 ) The perimeter of Δ ABC:
AB = √(3² + 4²) = √25 = 5 units
BC = √(1² + 1²) = √2 = 1.4 units
AC = √(3² + 4²) = √25 = 5 units
P = 5 + 1.4 + 5 = 11.4 units
4 ) Area of the figure ( approx.):
A ≈ ( 8 * 8) - 6.25 - 8 - 2.5 ≈ 47.25
Answer: C ) 50 ft²
5 ) Area under the curve:
A ≈ 0.5 * 3 + 0.5 * 3.5 + 0.5 * 4 + 0.5 * 4.5 + 0.5 * 5 + 0.5 * 4.5 + 0.5 * 4 +
+ 0.5 * 3 ≈ 0.5 * 31.5 ≈ 15.6
Answer: B ) 15 units²

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A vehicle is moving at a constant speed travels 45 miles in 3/4 hour. The driver thinks he will be late to a meeting that is sti

Ivahew [28]

The unit rate is 60 miles per hour and the driver will reach before time with the calculated constant speed

Step-by-step explanation:

Given

Distance = d = 45 miles

Time = t = 3/4 hour

The unit rate is defined as the distance per unit time. In this case, the unit rate can also be called speed.

So,

$s = \frac{d}{t}\\s = \frac{45}{\frac{3}{4}}\\s = 45 * \frac{4}{3}\\s = 60\ miles\ per\ hour$

Using this unit rate we can see if the car can travel 65 miles in 1.25 hours or not

Given

Distance = d1 = 65 miles

Speed = s = 60 miles per hour

Putting the values in the formula for speed

$s = \frac{d_1}{t_1}\\60 = \frac{65}{t_1}\\t_1 = \frac{65}{60}\\t_1 = 1.08\ hours$

As we can see that 1.08 is less than 1.25 so the driver will reach the meeting before time if he drives on a constant speed of 60 miles per hour

Hence,

The unit rate is 60 miles per hour and the driver will reach before time with the calculated constant speed

Keywords: Speed, unit rate

Learn more about speed at:

#LearnwithBrainly

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2 years ago

How do I solve this triangle?

svetlana [45]

Answer:

check the length and the angles and check the height of it

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2 years ago

Please!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! i give brainliest

creativ13 [48]

Answer:

2over1 multiply by 6over 3then you devide both sides by the given numbers then answer is 6woal number 1out of 6

6 0

1 year ago

What is GE ? <br><br><br> Enter your answer in the box.

harina [27]

Since ZY bisects GE and XY bisects EF, and both ZY and XY both bisect GF, then XY ~ ZE and ZY ~ XE.
Therefore ZE = XY = 5
And GE = 2× ZE (because bisected segments are = and therefore ×2 = long segment).
So GE = 2ZE = 2×5 = 10

6 0

2 years ago

Read 2 more answers

Arm Span(x) Height(y)

natita [175]

Answer:

Here's what I get.

Step-by-step explanation:

1. Representation of data

I used Excel to create a scatterplot of the data, draw the line of best fit, and print the regression equation.

2. Line of best fit

(a) Variables

I chose arm span as the dependent variable (y-axis) and height as the independent variable (x-axis).

It seems to me that arm span depends on your height rather than the other way around.

(b) Regression equation

The calculation is easy but tedious, so I asked Excel to do it.

For the equation y = ax + b, the formulas are

$a = \dfrac{\sum y \sum x^{2} - \sum x \sumxy}{n\sum x^{2}- \left (\sum x\right )^{2}}\\\\b = \dfrac{n\sumx y - \sum x \sumxy}{n\sum x^{2}- \left (\sum x\right )^{2}}$

This gave the regression equation:

y = 1.0595x - 4.1524

(c) Interpretation

The line shows how arm span depends on height.

The slope of the line says that arm span increases about 6 % faster than height.

The y-intercept is -4. If your height is zero, your arm length is -4 in (both are impossible).

(d) Residuals

$\begin{array}{cccr}&\textbf{Arm Span} & \textbf{Arm Span}&\\\textbf{Height/in} &\textbf{Actual} & \textbf{Predicted}&\textbf{Residual}\\25 & 19 & 22.3 & -3.3\\40 & 41 & 38.2 & 2.8\\55 & 51 & 54.1 & -3.1\\65 & 67 & 62.6 & 4.4\\ \end{array}$

The residuals appear to be evenly distributed above and below the predicted values.

A graph of all the residuals confirms this observation.

The equation usually predicts arm span to within 4 in.

(e) Predictions

(i) Height of person with 66 in arm span

$\begin{array}{rcl}y& = & 1.0595x - 4.1524\\66 & = & 1.0595x - 4.1524\\70.1524 & = & 1.0595x\\x & = & \dfrac{70.1524}{1.0595}\\\\& = & \textbf{66 in}\\\end{array}\\\text{A person with an arm span of 66 in should have a height of about $\large \boxed{\textbf{66 in}}$}$

(ii) Arm span of 74 in tall person

$\begin{array}{rcl}y& = & 1.0595x - 4.1524\\& = & 1.0595\times74 - 4.1524\\& = & 78.4030 - 4.1524\\& = & \textbf{74 in}\\\end{array}\\\text{ A person who is 74 in tall should have an arm span of $\large \boxed{\textbf{74 in}}$}$

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2 years ago