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nalin [4]
3 years ago
10

Find a solution to the following system of equations.

Mathematics
2 answers:
Flauer [41]3 years ago
8 0

b. (-1,2)
( - 12



julsineya [31]3 years ago
4 0
<span><span> {x,y} = {-1,2}</span> 
</span><span> [2] 5y = -3x + 7 [2] y = -3x/5 + 7/5</span>

// Plug this in for variable  y  in equation [1]

<span><span>  [1] -5x + 2•(-3x/5+7/5) = 9 </span><span>  [1] -31x/5 = 31/5 </span><span>  [1] -31x = 31 </span></span>

// Solve equation [1] for the variable  x  

<span><span>  [1] 31x = - 31</span>  <span>  [1] x = - 1</span> </span>

// By now we know this much :

<span><span>  x = -1</span> <span>  y = -3x/5+7/5</span></span>

<span>// Use the  x  value to solve for  y  
</span>

<span>   y = -(3/5)(-1)+7/5 = 2 </span>Solution :<span><span> {x,y} = {-1,2}</span>  </span>
<span>
</span>
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zmey [24]
Area= 2πr

So, 

If you were to multiply the radius by 2 since 2 is not in the equations, 

4*2= 8

8π ft^2 would be the correct answer.

I hope this helps!
~kaikers
5 0
3 years ago
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Danielle will use the instructions in the box below to make a cleaning solution I
melisa1 [442]
The answer is, A. 13/2 = w/5
6 0
3 years ago
Ophelia has 5 flower less than Daisy. Together they have 20 flowers. How many flowers have each of them?
dangina [55]
20 divided by four is 5 so maybe it is four.


I tried
7 0
3 years ago
Can someone show me how to do Mean absolute deviation
morpeh [17]
To find the mean of a set, add up all of the numbers and divide by how many numbers you have. For the first set:
\mu=\frac{10.7+2.4}2=\frac{13.1}2=6.55
For the second set:
\mu=\frac{13.7+2.5}2=\frac{16.2}2=8.1

To find the mean absolute deviation, (MAD) find the mean of the distances of each number from the mean.
For the first set: 
MAD=\frac{|10.7-6.55|+|2.4-6.55|}2=\frac{4.15+4.15}2=\frac{8.3}2=4.15
For the second set:
MAD=\frac{|13.7-8.1|+|2.5-8.1|}2=\frac{5.6+5.6}2=\frac{11.2}2=5.6
Note that when you only have two data points the mean is directly between them, which is why the distances are the same.

The means-to-MAD ratio is simply that, divide one by the other and that's it.
For the first set:
6.55\div4.15=1.57831325
For the second set:
8.1\div5.6=1.44642857
5 0
3 years ago
If you have a cubic polynomial of the form y = ax^3 + bx^2 + cx + d and lets say it passes through the points (2,28), (-1, -5),
belka [17]

Answer:

a = 3

b = 2

c = 0

d = -4

Step-by-step explanation:

Form 4 equations and solve simultaneously

28 = a(2)³ + b(2)² + c(2) + d

28 = 8a + 4b + 2c + d (1)

-5 = -a + b - c + d (2)

220 = 64a + 16b + 4c + d (3)

-20 = -8a + 4b - 2c + d (4)

(1) + (4)

28 = 8a + 4b + 2c + d

-20 = -8a + 4b - 2c + d

8 = 8b + 2d

d = 4 - 4b

Equation (2)

c = -a + b + d + 5

c = -a + b + 4 - 4b+ 5

c = -a - 3b + 9

28 = 8a + 4b + 2c + d (1)

28 = 8a + 4b + 2(-a - 3b + 9) + 4 - 4b

28 = 6a - 6b + 22

6a - 6b = 6

a - b = 1

a = b + 1

220 = 64a + 16b + 4c + d (3)

220 = 64(b + 1) + 16b + 4(-b - 1 - 3b + 9) + 4 - 4b

220 = 60b + 100

60b = 120

b = 2

a = 2 + 1

a = 3

c = -3 - 3(2) + 9

c = 0

d = 4 - 4(2)

d = -4

8 0
3 years ago
Read 2 more answers
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