The sum of three consecutive numbers is greater than 40. The inequality that represents this is x + x + 1 + x + 2 > 40. Which
values of x hold true for the inequality?
2 answers:
Answer:
All integers greater than 12 (13 onwards) satisfy the inequality
Step-by-step explanation:
x + x + 1 + x + 2 > 40.
3x + 3 > 40
3x > 37
x > 12.3333
All integers greater than 12 (13 onwards) satisfy the inequality
Answer:
3x > 37
x > 12.333
Thus, 13 and 15 satisfy
Step-by-step explanation:
hope this helps
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