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beks73 [17]
3 years ago
6

The sum of three consecutive numbers is greater than 40. The inequality that represents this is x + x + 1 + x + 2 > 40. Which

values of x hold true for the inequality?
Mathematics
2 answers:
Aloiza [94]3 years ago
8 0

Answer:

All integers greater than 12 (13 onwards) satisfy the inequality

Step-by-step explanation:

x + x + 1 + x + 2 > 40.

3x + 3 > 40

3x > 37

x > 12.3333

All integers greater than 12 (13 onwards) satisfy the inequality

Brut [27]3 years ago
3 0

Answer:

3x > 37

x > 12.333

Thus, 13 and 15 satisfy

Step-by-step explanation:

hope this helps

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Answer:

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Taking logarithm with the base of e (㏑) both sides we get,

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