Geometry Question Please Answer Quick!

Mathematics

1 answer:

kicyunya [14]2 years ago

6 0

The area is (BK) times (AK or CK).

If you have no numbers given, it's not possible to find the length of BK, or the actual number that represents the area.

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Solve the equation. Check for extraneous solutions<br><br> please help!!!

lozanna [386]

!z!=a→z=a or z=-a; z=4x+3, a=9+2x

!4x+3!=9+2x
1) 4x+3=9+2x
Solving for x:
4x+3-3-2x=9+2x-3-2x
2x=6
2x/2=6/2
x=3

Checking for extraneous solution:
!4x+3!=9+2x
x=3→!4(3)+3!=9+2(3)
!12+3!=9+6
!15!=15
15=15 Ok, then x=3 is not a extraneous solution

2) 4x+3=-(9+2x)
Solving for x:
4x+3=-9-2x
4x+3-3+2x=-9-2x-3+2x
6x=-12
6x/6=-12/6
x=-2

Checking for extraneous solution:
!4x+3!=9+2x
x=-2→!4(-2)+3!=9+2(-2)
!-8+3!=9-4
!-5!=5
5=5 Ok, then x=-2 is not a extraneous solution

Answer:
x = -2 or 3

4 0

3 years ago

Help first one gets brainllest

kherson [118]

Answer:

x = 1 $\frac{1}{4}$

Step-by-step explanation:

Expressing the diagram as an equation , that is

6x - 3 = 4 $\frac{1}{2}$ = $\frac{9}{2}$ ( multiply through by 2 to clear the fraction )

12x - 6 = 9 ( add 6 to both sides )

12x = 15 ( divide both sides by 12 )

x = $\frac{15}{12}$ = $\frac{5}{4}$ = 1 $\frac{1}{4}$

4 0

3 years ago

Help ASAP math homework

poizon [28]

See attachment for graph.

Notes: graph each line as if they are "equal".
Then draw the lines as:
dashed for < and >
solid for ≤ and ≥
Next, choose a test point and plug it into both equations. If the result is True for BOTH equations, then shade that section.