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3 years ago

How to write the simplest polynomial function of -2i and 1+i

Mathematics

1 answer:

erica [24]3 years ago

3 0

The simplest polynomial function for it is 1- i

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What is the area of the poster board that she has left

steposvetlana [31]

Find the area of the parallelogram, find the area of the triangle, then subtract the triangle's area from the area of the parallelogram.

Area of Parallelogram:
A= base * height
A= 20 in * 10 in
A= 200 in^2

Area of Triangle:
A= 1/2 base * height
A= 1/2 (10 in)(9 in)
A= 1/2 (90)
A= 45 in ^2

Area of Poster Left:
subtract the difference
A= Parallelogram Area - Triangle Area
A= 200 in^2 - 45 in^2
A= 155 in^2

ANSWER: 155 in^2 is the area of the poster board she has left.

Hope this helps! :)

5 0

3 years ago

Divide.<br> Write your answer in simplest form.<br> -6/7 divided by (-5/4) =?

yulyashka [42]

Answer:

$\sf \dfrac{24}{35}$

Step-by-step explanation:

Use KCF method for fraction division.

Keep the first fraction.
Change the division operation to multiplication.
Flip the second fraction.

$\sf \dfrac{-6}{7} \div \dfrac{-5}{4}=\dfrac{-6}{7}*\dfrac{-4}{5}$

$\sf =\dfrac{(-6)*(-4)}{7*5}\\\\=\dfrac{24}{35}$

8 0

1 year ago

Read 2 more answers

What’s the answer for A B and C?

dimaraw [331]

Answer:

a = 2

b = 3

c = 8

Step-by-step explanation:

First, let us look at the first two (far left) fractions to solve for a.

Since $2^5 = 2^5$ , nothing needs to change in the numerator. 4 = $2^{2}$

a = 2.

Next, we will look at the first and third fractions to solve for b.

$2^5$ = 32

32 / 4 = 8

$2^3$ = 8

b = 3

Lastly, we will solve for c.

All of these fractions simplify to 8 and are equal to each other.

c = 8

6 0

1 year ago

Find the distance between the two points in simplest radical form.<br> (-1,9) and (4, -3)

jolli1 [7]

Answer:

GIVEN BY POINTS :-

( -1, 9) , ( 4 , -3)

Here ,

$\bullet \: \: x _{1} = - 1 \\ \bullet \: \: x _{2} = 4 \\ \bullet \: \: y _{1} = 9 \\ \bullet \: \: y _{2} = - 3 \\$

Using Distance formula :

$= > \sf d = \sqrt{( {x _{2} - x _{1}) }^{2} + {( {y _{2} - y _{1}) }^{2} } } \\ \\ = > \sf d = \sqrt{ ({ 4 + 1)}^{2} + { ( - 3 - 9)}^{2} } \\ \\ = > \sf d = \sqrt{ {5}^{2} + {( - 12)}^{2} } \\ \\ = > \sf d = \sqrt{25 + 144} \\ \\ = > \sf d = \sqrt{169} \\ \\ = > \boxed{ \sf{ d = 13\:units }}\\$