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3 years ago

What's the median of 80,84,86,87,90,91,92,94,100

2 answers:

8 0

Hello there, and thank you for posting your question here on brainly.

The median is the middle number in the set.

Take one number out from each side, until you get the one in the middle.

In that case, your answer is 90.

Hope this helped!! ☺♥

valkas [14]3 years ago

6 0

To find median you arrange the value from the smallest value to the largest value then the value in the middle is the medium

Medium =90

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Y=0.2(4)x is it exponential growth or decay

Dmitry [639]

Answer:

growth

Step-by-step explanation:

This is of the form

y = ab^x where a is the initial value and b is either growth or decay

if b > 1 then it is growth

b <1 it is decay

a = .2

b = 4

Since b>1 it is growth

5 0

3 years ago

Can anyone please help me on questions 5-8?

alisha [4.7K]

5) 3.96 gallons

6) 6.09 kilograms

5 0

2 years ago

I need help with #5 an explanation might be nice too!! (will give brainliest!) and 50 points.

julsineya [31]

Answer:

2600 yd cubed

Step-by-step explanation:

13 times 20 is 260

260 times 10 is 2600

8 0

2 years ago

A fire truck has a long ladder that is made of 3 sections. Each section is 43/4 meters long.

Amanda [17]

You need to simplify the improper fraction into a mixed number.

43/4 = 10 3/4 (or 10.75)
You will want to have your answer as a mixed number, but multiplying might be easier if you use the decimal for calculations.

Now you multiply your mixed number or decimal by 3 (3 sections).

10.75 * 3 = 32.25 or 32 1/4

Your answer would be 32 1/4 meters.

Hope this helps :)

5 0

2 years ago

Problem Solving

Aleks [24]

Answer:

A) $\theta=30^\circ+180n^\circ$

Step-by-step explanation:

$tan\theta=4tan\theta-\sqrt{3}\\\\-3tan\theta=-\sqrt{3}\\\\9tan^2\theta=3\\\\tan^2\theta=\frac{3}{9}\\ \\tan^2\theta=\frac{1}{3}\\ \\\frac{1-cos(2\theta)}{1+cos(2\theta)}=\frac{1}{3}\\ \\ 3-3cos(2\theta)=1+cos(2\theta)\\\\2-3cos(2\theta)=cos(2\theta)\\\\2=4cos(2\theta)\\\\\frac{2}{4}=cos(2\theta)\\ \\\frac{1}{2}=cos(2\theta)\\ \\2\theta=60^\circ+360n^\circ\\\\\theta=30^\circ+180n^\circ$

Recall the identity $tan^2(\theta)=\frac{1-cos(2\theta)}{1+cos(2\theta)}$

5 0

1 year ago