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2 years ago

What is the sum of the angle of a polygon of 62 sides

Mathematics

1 answer:

kiruha [24]2 years ago

8 0

Sum of all angles in a 62 sided polygon = 10800°. (Mark me as brainliest pls!)

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Cual es la mitad de dos tercios

Bumek [7]

Un tercio ,,,,.........,,.

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3 years ago

-3+m --------- = 10 9

mafiozo [28]

Answer:

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Step-by-step explanation:

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3 years ago

Here are measurements (in millime- ters) of a critical dimension on an SRS of 16 of the more than 200 auto engine crankshafts pr

Juli2301 [7.4K]

Answer:

(23.97, 24.03)

Step-by-step explanation:

Given the data:

224.120 224.001 224.017 223.982 223.989 223.961 223.960 224.089 223.987 223.976 223.902 223.980 224.098 224.057 223.913 223.999

Confidence interval = m ± Zcritical(s/√n)

n = sample size = 16

Zcritical at 95% = 1.96

Using calculator :

Sample mean, m = 224.0019

Standard deviation, s = 0.0618

Lower bound : 24.0019 - 1.96(0.0618/√16) = 23.971618

Upper bound : 24.0019 + 1.96(0.0618/√16) = 24.032182

(23.97, 24.03)

3 0

2 years ago

I NEED HELP PLEASEEE

Gwar [14]

Answer:

b = $\sqrt{333}$

Step-by-step explanation:

1. We can use the Pythagorean Theorem to find the missing side, b.

$14^2 + b^2 = 23^2$

2. (Solving)

Step 1: Simplify both sides of the equation.

$(14*14)+b^2 =(23*23)$
$196 + b^2 = 529$

Step 2: Subtract 196 from both sides.

$196 + b^2 - 196 = 529 - 196$
$b^2 = 333$

Step 3: Take square root of both sides.

$\sqrt{b^2} = \sqrt{333}$
$b = \sqrt{333}$

Step 4: Check if solution is correct.

$14^2 + \sqrt{333^2} = 23^2$
$(14*14)+(\sqrt{333} *\sqrt{333})=23*23$
$196 + 333 = 529$
$529 = 529$

Therefore, b = $\sqrt{333}$ .

6 0

2 years ago

Read 2 more answers

What is the value of 1/4 to the power of 3

LenaWriter [7]

Answer:

1/64

Step-by-step explanation:

hope that helps

7 0

3 years ago

What is the sum of the angle of a polygon of 62 sides ​

What is the sum of the angle of a polygon of 62 sides